有没有一个函数生成一个随机int数在C?或者我必须使用第三方库?


当前回答

试试这个,我把上面已经提到的一些概念放在一起:

/*    
Uses the srand() function to seed the random number generator based on time value,
then returns an integer in the range 1 to max. Call this with random(n) where n is an integer, and you get an integer as a return value.
 */

int random(int max) {
    srand((unsigned) time(NULL));
    return (rand() % max) + 1;
}

其他回答

<stdlib.h>中的rand()函数返回一个介于0和RAND_MAX之间的伪随机整数。你可以使用srand(unsigned int seed)来设置种子。

通常的做法是将%操作符与rand()结合使用以获得不同的范围(但请记住,这在一定程度上破坏了一致性)。例如:

/* random int between 0 and 19 */
int r = rand() % 20;

如果你真的在乎一致性,你可以这样做:

/* Returns an integer in the range [0, n).
 *
 * Uses rand(), and so is affected-by/affects the same seed.
 */
int randint(int n) {
  if ((n - 1) == RAND_MAX) {
    return rand();
  } else {
    // Supporting larger values for n would requires an even more
    // elaborate implementation that combines multiple calls to rand()
    assert (n <= RAND_MAX)

    // Chop off all of the values that would cause skew...
    int end = RAND_MAX / n; // truncate skew
    assert (end > 0);
    end *= n;

    // ... and ignore results from rand() that fall above that limit.
    // (Worst case the loop condition should succeed 50% of the time,
    // so we can expect to bail out of this loop pretty quickly.)
    int r;
    while ((r = rand()) >= end);

    return r % n;
  }
}

如果您需要128个安全随机位,符合RFC 1750的解决方案是读取已知可以生成可用熵位的硬件源(例如旋转磁盘)。更好的是,好的实现应该使用混合函数组合多个源,并最终通过重新映射或删除输出来消除输出分布的倾斜。

如果你需要更多的比特,你需要做的就是从128个安全随机比特的序列开始,并将其拉伸到所需的长度,将其映射到人类可读的文本等等。

如果你想在C中生成一个安全的随机数,我将遵循这里的源代码:

https://wiki.sei.cmu.edu/confluence/display/c/MSC30-C.+Do+not+use+the+rand%28%29+function+for+generating+pseudorandom+numbers

注意,对于Windows bbcryptgenrandom是使用的,而不是CryptGenRandom,在过去的20年里已经变得不安全。您可以亲自确认BCryptGenRandom符合RFC 1750。

For POSIX-compliant operating systems, e.g. Ubuntu (a flavor of Linux), you can simply read from /dev/urandom or /dev/random, which is a file-like interface to a device that generates bits of entropy by combining multiple sources in an RFC 1750 compliant fashion. You can read a desired number of bytes from these "files" with read or fread just like you would any other file, but note that reads from /dev/random will block until a enough new bits of entropy are available, whereas /dev/urandom will not, which can be a security issue. You can get around that by checking the size of the available entropy pool, either my reading from entropy_avail, or by using ioctl.

我的极简解决方案应该适用于范围内的随机数[min, max)。在调用函数之前使用srand(time(NULL))。

int range_rand(int min_num, int max_num) {
    if (min_num >= max_num) {
        fprintf(stderr, "min_num is greater or equal than max_num!\n"); 
    }
    return min_num + (rand() % (max_num - min_num));
} 

在我最近的应用程序中,我遇到了一个严重的伪随机数生成器问题:我多次通过Python脚本调用我的C程序,并使用以下代码作为种子:

srand(time(NULL))

然而,由于:

Rand将生成相同的伪随机序列,在srand中给出相同的种子(参见man srand); 如前所述,time函数每秒只会变化:如果应用程序在同一秒内运行多次,time每次都会返回相同的值。

我的程序生成了相同的数字序列。 你可以做三件事来解决这个问题:

mix time output with some other information changing on runs (in my application, the output name): srand(time(NULL) | getHashOfString(outputName)) I used djb2 as my hash function. Increase time resolution. On my platform, clock_gettime was available, so I use it: #include<time.h> struct timespec nanos; clock_gettime(CLOCK_MONOTONIC, &nanos) srand(nanos.tv_nsec); Use both methods together: #include<time.h> struct timespec nanos; clock_gettime(CLOCK_MONOTONIC, &nanos) srand(nanos.tv_nsec | getHashOfString(outputName));

选项3确保了你(据我所知)最好的种子随机性,但它可能只会在非常快速的应用中产生差异。 在我看来,选择2是一个安全的赌注。

你可以生成随机字符,然后将它们视为int:

#include <stdlib.h>
#include <stdio.h>

typedef double rand_type; // change double to int

rand_type my_rand() {
    char buff[sizeof(rand_type)];
    for (size_t i = 0 ; i < sizeof(rand_type) ; ++i)
        buff[i] = (char) rand();
    return *(rand_type *) buff;
}

int main() {
    int i ; // srand as you want
    for (i = 0 ; i < 10 ; ++i)
        printf("%g\n", my_rand()); // change %g to %d
    return 0 ;
}