如何从文件扩展名中获得MIME类型?
当前回答
为了使这篇文章更全面,对于。net核心开发人员有FileExtensionContentTypeProvider类,它涵盖了官方的MIME内容类型。
它在幕后工作——根据文件扩展名在Http响应头中设置ContentType。
如果您需要特殊的MIME类型,请参阅自定义MIME类型的示例:
public void Configure(IApplicationBuilder app)
{
// Set up custom content types -associating file extension to MIME type
var provider = new FileExtensionContentTypeProvider();
// Add new mappings
provider.Mappings[".myapp"] = "application/x-msdownload";
provider.Mappings[".htm3"] = "text/html";
provider.Mappings[".image"] = "image/png";
// Replace an existing mapping
provider.Mappings[".rtf"] = "application/x-msdownload";
// Remove MP4 videos.
provider.Mappings.Remove(".mp4");
app.UseStaticFiles(new StaticFileOptions()
{
FileProvider = new PhysicalFileProvider(
Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
RequestPath = new PathString("/MyImages"),
ContentTypeProvider = provider
});
app.UseDirectoryBrowser(new DirectoryBrowserOptions()
{
FileProvider = new PhysicalFileProvider(
Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
RequestPath = new PathString("/MyImages")
});
}
其他回答
我已经编写了一个程序来获取和转换Apache mime。类型文件到c#字典<字符串,字符串>的关键文件扩展名。这里的。
实际的输出是这个文件(但是您可能希望获取它并再次运行它,以防Apache文件在我上次运行之后已经更新)。
public static Dictionary<string, string> MimeTypes = new Dictionary<string, string>
{
{ "123", "application/vnd.lotus-1-2-3" },
{ "3dml", "text/vnd.in3d.3dml" },
{ "3g2", "video/3gpp2" },
{ "3gp", "video/3gpp" },
{ "7z", "application/x-7z-compressed" },
{ "aab", "application/x-authorware-bin" },
{ "aac", "audio/x-aac" },
{ "aam", "application/x-authorware-map" },
{ "aas", "application/x-authorware-seg" },
{ "abw", "application/x-abiword" },
...
为了使这篇文章更全面,对于。net核心开发人员有FileExtensionContentTypeProvider类,它涵盖了官方的MIME内容类型。
它在幕后工作——根据文件扩展名在Http响应头中设置ContentType。
如果您需要特殊的MIME类型,请参阅自定义MIME类型的示例:
public void Configure(IApplicationBuilder app)
{
// Set up custom content types -associating file extension to MIME type
var provider = new FileExtensionContentTypeProvider();
// Add new mappings
provider.Mappings[".myapp"] = "application/x-msdownload";
provider.Mappings[".htm3"] = "text/html";
provider.Mappings[".image"] = "image/png";
// Replace an existing mapping
provider.Mappings[".rtf"] = "application/x-msdownload";
// Remove MP4 videos.
provider.Mappings.Remove(".mp4");
app.UseStaticFiles(new StaticFileOptions()
{
FileProvider = new PhysicalFileProvider(
Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
RequestPath = new PathString("/MyImages"),
ContentTypeProvider = provider
});
app.UseDirectoryBrowser(new DirectoryBrowserOptions()
{
FileProvider = new PhysicalFileProvider(
Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
RequestPath = new PathString("/MyImages")
});
}
如果你不想增加额外的依赖关系,并且仍然想要版本独立的请求,你可以把这个关于如何在不同的。net版本中获得MIME-Type的答案与这个关于多个。net框架版本的条件构建的答案混合在一起。
我做的第一件事是编辑我的项目文件。在最后一个构建定义之后,我添加了第二个答案中所述的属性组:
<PropertyGroup>
<DefineConstants Condition=" !$(DefineConstants.Contains(';NET')) ">$(DefineConstants);$(TargetFrameworkVersion.Replace("v", "NET").Replace(".", ""))</DefineConstants>
<DefineConstants Condition=" $(DefineConstants.Contains(';NET')) ">$(DefineConstants.Remove($(DefineConstants.LastIndexOf(";NET"))));$(TargetFrameworkVersion.Replace("v", "NET").Replace(".", ""))</DefineConstants>
</PropertyGroup>
现在我为MimeExtensionHelper提供了一个与第一个答案不同的实现,并为所有来自。net 4.5或更高版本的客户端提供了一个额外的实现,只需调用System.Web.MimeMapping.GetMimeMapping:
#if (NET10 || NET11 || NET20 || NET30 || NET35)
public static class MimeExtensionHelper
{
static object locker = new object();
static MethodInfo getMimeMappingMethodInfo;
static MimeExtensionHelper()
{
Type mimeMappingType = Assembly.GetAssembly(typeof(HttpRuntime)).GetType("System.Web.MimeMapping");
if (mimeMappingType == null)
throw new SystemException("Couldnt find MimeMapping type");
ConstructorInfo constructorInfo = mimeMappingType.GetConstructor(BindingFlags.NonPublic | BindingFlags.Instance, null, Type.EmptyTypes, null);
if (constructorInfo == null)
throw new SystemException("Couldnt find default constructor for MimeMapping");
mimeMapping = constructorInfo.Invoke(null);
if (mimeMapping == null)
throw new SystemException("Couldnt find MimeMapping");
getMimeMappingMethodInfo = mimeMappingType.GetMethod("GetMimeMapping", BindingFlags.Static | BindingFlags.NonPublic);
if (getMimeMappingMethodInfo == null)
throw new SystemException("Couldnt find GetMimeMapping method");
if (getMimeMappingMethodInfo.ReturnType != typeof(string))
throw new SystemException("GetMimeMapping method has invalid return type");
if (getMimeMappingMethodInfo.GetParameters().Length != 1 && getMimeMappingMethodInfo.GetParameters()[0].ParameterType != typeof(string))
throw new SystemException("GetMimeMapping method has invalid parameters");
}
public static string GetMimeType(string fileName)
{
lock (locker)
{
return (string)getMimeMappingMethodInfo.Invoke(null, new object[] { fileName });
}
}
}
#elif NET40
public static class MimeExtensionHelper
{
static object locker = new object();
static MethodInfo getMimeMappingMethodInfo;
static MimeExtensionHelper()
{
Type mimeMappingType = Assembly.GetAssembly(typeof(HttpRuntime)).GetType("System.Web.MimeMapping");
if (mimeMappingType == null)
throw new SystemException("Couldnt find MimeMapping type");
getMimeMappingMethodInfo = mimeMappingType.GetMethod("GetMimeMapping", BindingFlags.Static | BindingFlags.NonPublic | BindingFlags.Public);
if (getMimeMappingMethodInfo == null)
throw new SystemException("Couldnt find GetMimeMapping method");
if (getMimeMappingMethodInfo.ReturnType != typeof(string))
throw new SystemException("GetMimeMapping method has invalid return type");
if (getMimeMappingMethodInfo.GetParameters().Length != 1 && getMimeMappingMethodInfo.GetParameters()[0].ParameterType != typeof(string))
throw new SystemException("GetMimeMapping method has invalid parameters");
}
public static string GetMimeType(string fileName)
{
lock (locker)
{
return (string)getMimeMappingMethodInfo.Invoke(null, new object[] { fileName });
}
}
}
#else // .NET 4.5 or later
public static class MimeExtensionHelper
{
public static string GetMimeType(string fileName)
{
return MimeMapping.GetMimeMapping(fileName);
}
}
#endif
同样在。net 4.5之前的版本中,静态MimeMapping类拥有一个名为_mappingDictionary的静态实例(类型为MimeMapping. mimemappingdictionarybase),您可以从反射请求该实例,以便添加可能还不支持的新的MIME-Types。
你可以使用mimemaps类。我认为这是最简单的方法。我也给出了mimemapping的导入。因为我觉得找这些类的导入很麻烦。
import org.springframework.boot.web.server.MimeMappings;
MimeMappings mm=new MimeMappings();
String mimetype = mm.get(fileExtension);
System.out.println(mimetype);
FileExtension处理文件扩展名,而不是Mime。用户可以更改文件扩展名,因此请检查Mime。代码示例通过文件扩展名关联Mime,这是错误的,不能工作。
需要获取内容类型文件,并检查表Mime contetType该文件根据文件扩展名。现在,如何获得文件的内容类型?
使用FileUpload是这样的: 现在,如果我已经有文件,捕捉你的ContentType?
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