如何从文件扩展名中获得MIME类型?


当前回答

为了使这篇文章更全面,对于。net核心开发人员有FileExtensionContentTypeProvider类,它涵盖了官方的MIME内容类型。

它在幕后工作——根据文件扩展名在Http响应头中设置ContentType。

如果您需要特殊的MIME类型,请参阅自定义MIME类型的示例:

public void Configure(IApplicationBuilder app)
{
    // Set up custom content types -associating file extension to MIME type
    var provider = new FileExtensionContentTypeProvider();
    // Add new mappings
    provider.Mappings[".myapp"] = "application/x-msdownload";
    provider.Mappings[".htm3"] = "text/html";
    provider.Mappings[".image"] = "image/png";
    // Replace an existing mapping
    provider.Mappings[".rtf"] = "application/x-msdownload";
    // Remove MP4 videos.
    provider.Mappings.Remove(".mp4");

    app.UseStaticFiles(new StaticFileOptions()
    {
        FileProvider = new PhysicalFileProvider(
            Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
        RequestPath = new PathString("/MyImages"),
        ContentTypeProvider = provider
    });

    app.UseDirectoryBrowser(new DirectoryBrowserOptions()
    {
        FileProvider = new PhysicalFileProvider(
            Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
        RequestPath = new PathString("/MyImages")
    });
}

其他回答

我已经编写了一个程序来获取和转换Apache mime。类型文件到c#字典<字符串,字符串>的关键文件扩展名。这里的。

实际的输出是这个文件(但是您可能希望获取它并再次运行它,以防Apache文件在我上次运行之后已经更新)。

public static Dictionary<string, string> MimeTypes = new Dictionary<string, string>
{
  { "123", "application/vnd.lotus-1-2-3" },
  { "3dml", "text/vnd.in3d.3dml" },
  { "3g2", "video/3gpp2" },
  { "3gp", "video/3gpp" },
  { "7z", "application/x-7z-compressed" },
  { "aab", "application/x-authorware-bin" },
  { "aac", "audio/x-aac" },
  { "aam", "application/x-authorware-map" },
  { "aas", "application/x-authorware-seg" },
  { "abw", "application/x-abiword" },
  ...

为了使这篇文章更全面,对于。net核心开发人员有FileExtensionContentTypeProvider类,它涵盖了官方的MIME内容类型。

它在幕后工作——根据文件扩展名在Http响应头中设置ContentType。

如果您需要特殊的MIME类型,请参阅自定义MIME类型的示例:

public void Configure(IApplicationBuilder app)
{
    // Set up custom content types -associating file extension to MIME type
    var provider = new FileExtensionContentTypeProvider();
    // Add new mappings
    provider.Mappings[".myapp"] = "application/x-msdownload";
    provider.Mappings[".htm3"] = "text/html";
    provider.Mappings[".image"] = "image/png";
    // Replace an existing mapping
    provider.Mappings[".rtf"] = "application/x-msdownload";
    // Remove MP4 videos.
    provider.Mappings.Remove(".mp4");

    app.UseStaticFiles(new StaticFileOptions()
    {
        FileProvider = new PhysicalFileProvider(
            Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
        RequestPath = new PathString("/MyImages"),
        ContentTypeProvider = provider
    });

    app.UseDirectoryBrowser(new DirectoryBrowserOptions()
    {
        FileProvider = new PhysicalFileProvider(
            Path.Combine(Directory.GetCurrentDirectory(), @"wwwroot", "images")),
        RequestPath = new PathString("/MyImages")
    });
}

如果你不想增加额外的依赖关系,并且仍然想要版本独立的请求,你可以把这个关于如何在不同的。net版本中获得MIME-Type的答案与这个关于多个。net框架版本的条件构建的答案混合在一起。

我做的第一件事是编辑我的项目文件。在最后一个构建定义之后,我添加了第二个答案中所述的属性组:

<PropertyGroup>
    <DefineConstants Condition=" !$(DefineConstants.Contains(';NET')) ">$(DefineConstants);$(TargetFrameworkVersion.Replace("v", "NET").Replace(".", ""))</DefineConstants>
    <DefineConstants Condition=" $(DefineConstants.Contains(';NET')) ">$(DefineConstants.Remove($(DefineConstants.LastIndexOf(";NET"))));$(TargetFrameworkVersion.Replace("v", "NET").Replace(".", ""))</DefineConstants>
</PropertyGroup>

现在我为MimeExtensionHelper提供了一个与第一个答案不同的实现,并为所有来自。net 4.5或更高版本的客户端提供了一个额外的实现,只需调用System.Web.MimeMapping.GetMimeMapping:

#if (NET10 || NET11 || NET20 || NET30 || NET35)
public static class MimeExtensionHelper
{
    static object locker = new object();
    static MethodInfo getMimeMappingMethodInfo;

    static MimeExtensionHelper()
    {
        Type mimeMappingType = Assembly.GetAssembly(typeof(HttpRuntime)).GetType("System.Web.MimeMapping");

        if (mimeMappingType == null)
            throw new SystemException("Couldnt find MimeMapping type");

        ConstructorInfo constructorInfo = mimeMappingType.GetConstructor(BindingFlags.NonPublic | BindingFlags.Instance, null, Type.EmptyTypes, null);

        if (constructorInfo == null)
            throw new SystemException("Couldnt find default constructor for MimeMapping");

        mimeMapping = constructorInfo.Invoke(null);

        if (mimeMapping == null)
            throw new SystemException("Couldnt find MimeMapping");

        getMimeMappingMethodInfo = mimeMappingType.GetMethod("GetMimeMapping", BindingFlags.Static | BindingFlags.NonPublic);

        if (getMimeMappingMethodInfo == null)
            throw new SystemException("Couldnt find GetMimeMapping method");

        if (getMimeMappingMethodInfo.ReturnType != typeof(string))
            throw new SystemException("GetMimeMapping method has invalid return type");

        if (getMimeMappingMethodInfo.GetParameters().Length != 1 && getMimeMappingMethodInfo.GetParameters()[0].ParameterType != typeof(string))
            throw new SystemException("GetMimeMapping method has invalid parameters");
    }

    public static string GetMimeType(string fileName)
    {
        lock (locker)
        {
            return (string)getMimeMappingMethodInfo.Invoke(null, new object[] { fileName });
        }
    }
}
#elif NET40
public static class MimeExtensionHelper
{
    static object locker = new object();
    static MethodInfo getMimeMappingMethodInfo;

    static MimeExtensionHelper()
    {
        Type mimeMappingType = Assembly.GetAssembly(typeof(HttpRuntime)).GetType("System.Web.MimeMapping");

        if (mimeMappingType == null)
            throw new SystemException("Couldnt find MimeMapping type");           

        getMimeMappingMethodInfo = mimeMappingType.GetMethod("GetMimeMapping", BindingFlags.Static | BindingFlags.NonPublic | BindingFlags.Public);

        if (getMimeMappingMethodInfo == null)
            throw new SystemException("Couldnt find GetMimeMapping method");

        if (getMimeMappingMethodInfo.ReturnType != typeof(string))
            throw new SystemException("GetMimeMapping method has invalid return type");

        if (getMimeMappingMethodInfo.GetParameters().Length != 1 && getMimeMappingMethodInfo.GetParameters()[0].ParameterType != typeof(string))
            throw new SystemException("GetMimeMapping method has invalid parameters");
    }

    public static string GetMimeType(string fileName)
    {
        lock (locker)
        {
            return (string)getMimeMappingMethodInfo.Invoke(null, new object[] { fileName });
        }
    }
}
#else // .NET 4.5 or later
public static class MimeExtensionHelper
{
    public static string GetMimeType(string fileName)
    {
        return MimeMapping.GetMimeMapping(fileName);
    }
}
#endif

同样在。net 4.5之前的版本中,静态MimeMapping类拥有一个名为_mappingDictionary的静态实例(类型为MimeMapping. mimemappingdictionarybase),您可以从反射请求该实例,以便添加可能还不支持的新的MIME-Types。

你可以使用mimemaps类。我认为这是最简单的方法。我也给出了mimemapping的导入。因为我觉得找这些类的导入很麻烦。

import org.springframework.boot.web.server.MimeMappings;    
MimeMappings mm=new MimeMappings();
String mimetype = mm.get(fileExtension);
System.out.println(mimetype);

FileExtension处理文件扩展名,而不是Mime。用户可以更改文件扩展名,因此请检查Mime。代码示例通过文件扩展名关联Mime,这是错误的,不能工作。

需要获取内容类型文件,并检查表Mime contetType该文件根据文件扩展名。现在,如何获得文件的内容类型?

使用FileUpload是这样的: 现在,如果我已经有文件,捕捉你的ContentType?