我希望通过复制Java文件夹的内容并设置环境变量来确保一切都能正常工作。
我通常在虚拟机中运行安装程序，压缩\java文件夹内容，回到虚拟机的快照，然后解压缩压缩文件。
我找不到一个地方有最新的JRE / JDK压缩文件…
http://java.sun.com/javase/downloads/index.jsp
http://download.java.net/jdk6/
另外，假定sun的exe安装程序只是解压缩整个文件，而不会弄乱注册表、环境变量等等，这是否安全?
相关:在Windows上手动安装Java ?
-- 经过这么长时间，我找到了这个网站，似乎正是我要找的(2018-05-22)
当前回答
http://androidhost.org/D8wsv
您可以从上面的链接获取jre-7u75-windows-i586.zip。
其他回答
Sun JVM可以作为MSI，它可以从脚本执行。
http://java.sun.com/javase/6/docs/technotes/guides/deployment/deployment-guide/install-msi.html
下面提示中的命令包装为批处理脚本。保存为unpack.bat。然后将它与jdk/jre提取文件一起放置到dir。
@echo off
cd /d "%~dp0"
for /r %%x in (*.pack) do .\bin\unpack200 -r "%%x" "%%~dx%%~px%%~nx.jar"
The Process described by Igor and CharlesB Works to me, since IDE's like NetBeans and Eclipse permit specify the location of the JDK, even software like Apache Tomcat (the ZIP Distribution) use BASH - FILES to set it up (then specify the JDK location using relatives URI). I Have a USB-HardDisk With NetBeans, Eclipse, Apache Tomcat working with a JDK in "portable mode". I Had a way to extract a copy of the JDK from the installers files: Install it, Copy it in other place and then uninstall it. A dirty way to extract it, but was successfull. The place to put EXTRA - LIBS was: %PLACE_WHERE_JDK_ARE%\jre\lib\ext
安装在沙箱，并复制文件夹。
mkdir c:\JDK
cd c:\JDK
git clone https://bitbucket.org/ramazanpolat/jdk-8u112-windows-x64/
or
git clone https://bitbucket.org/ramazanpolat/jdk-8u112-windows-x86
