Smart Manoj回答:从文件夹中的所有图像制作一个.mp4电影

安装:

pip install imageio-ffmpeg
pip install imageio

代码:

import os
import imageio

root = r'path_to_folder_with_images'

images = []    
for subdir, dirs, files in os.walk(root):
    for file in files:
        images.append(imageio.imread(os.path.join(root,file)))

savepath = r'path_to_save_folder'
imageio.mimsave(os.path.join(savepath,'movie.mp4'), images)

PS:确保你的“文件”列表按照你想要的方式排序，如果你已经相应地保存了你的图像，你会节省一些时间

一个制作动图的简单函数:

import imageio
import pathlib
from datetime import datetime


def make_gif(image_directory: pathlib.Path, frames_per_second: float, **kwargs):
    """
    Makes a .gif which shows many images at a given frame rate.
    All images should be in order (don't know how this works) in the image directory

    Only tested with .png images but may work with others.

    :param image_directory:
    :type image_directory: pathlib.Path
    :param frames_per_second:
    :type frames_per_second: float
    :param kwargs: image_type='png' or other
    :return: nothing
    """
    assert isinstance(image_directory, pathlib.Path), "input must be a pathlib object"
    image_type = kwargs.get('type', 'png')

    timestampStr = datetime.now().strftime("%y%m%d_%H%M%S")
    gif_dir = image_directory.joinpath(timestampStr + "_GIF.gif")

    print('Started making GIF')
    print('Please wait... ')

    images = []
    for file_name in image_directory.glob('*.' + image_type):
        images.append(imageio.imread(image_directory.joinpath(file_name)))
    imageio.mimsave(gif_dir.as_posix(), images, fps=frames_per_second)

    print('Finished making GIF!')
    print('GIF can be found at: ' + gif_dir.as_posix())


def main():
    fps = 2
    png_dir = pathlib.Path('C:/temp/my_images')
    make_gif(png_dir, fps)

if __name__ == "__main__":
    main()

安装

pip install imageio-ffmpeg
pip install imageio

Code

import imageio
images = []
for filename in filenames:
    images.append(imageio.imread(filename))
imageio.mimsave('movie.mp4', images)

当保存为mp4而不是gif时，质量提高，大小从8Mb减少到80Kb

老问题，有很多很好的答案，但可能仍然对另一种选择感兴趣……

我最近在github (https://github.com/WarrenWeckesser/numpngw)上发布的numpngw模块可以从numpy数组写入动画PNG文件。(更新:numpngw现在在pypi: https://pypi.python.org/pypi/numpngw。)

例如，这个脚本:

import numpy as np
import numpngw


img0 = np.zeros((64, 64, 3), dtype=np.uint8)
img0[:32, :32, :] = 255
img1 = np.zeros((64, 64, 3), dtype=np.uint8)
img1[32:, :32, 0] = 255
img2 = np.zeros((64, 64, 3), dtype=np.uint8)
img2[32:, 32:, 1] = 255
img3 = np.zeros((64, 64, 3), dtype=np.uint8)
img3[:32, 32:, 2] = 255
seq = [img0, img1, img2, img3]
for img in seq:
    img[16:-16, 16:-16] = 127
    img[0, :] = 127
    img[-1, :] = 127
    img[:, 0] = 127
    img[:, -1] = 127

numpngw.write_apng('foo.png', seq, delay=250, use_palette=True)

创建:

你需要一个支持动画PNG的浏览器(直接或带有插件)才能看到动画。

我尝试了以下方法，非常有用:

首先下载Figtodat和images2gif库到本地目录。

其次，收集数组中的图形并将其转换为动画gif:

import sys
sys.path.insert(0,"/path/to/your/local/directory")
import Figtodat
from images2gif import writeGif
import matplotlib.pyplot as plt
import numpy

figure = plt.figure()
plot   = figure.add_subplot (111)

plot.hold(False)
    # draw a cardinal sine plot
images=[]
y = numpy.random.randn(100,5)
for i in range(y.shape[1]):
    plot.plot (numpy.sin(y[:,i]))  
    plot.set_ylim(-3.0,3)
    plot.text(90,-2.5,str(i))
    im = Figtodat.fig2img(figure)
    images.append(im)

writeGif("images.gif",images,duration=0.3,dither=0)

现在我在用ImageMagick。我将帧保存为PNG文件，然后从Python中调用ImageMagick的convert.exe来创建一个动画GIF。这种方法的好处是我可以为每一帧单独指定帧持续时间。不幸的是，这取决于ImageMagick安装在机器上。他们有一个Python包装器，但它看起来很糟糕，不受支持。还在考虑其他建议。