要向所有客户端发送内容,您可以使用:
io.sockets.emit('response', data);
要接收来自客户的信息,您可以使用:
socket.on('cursor', function(data) {
...
});
如何将这两者结合起来,以便在服务器上从客户端接收消息时,将该消息发送给除发送消息的用户之外的所有用户?
socket.on('cursor', function(data) {
io.sockets.emit('response', data);
});
我是否必须通过发送带有消息的client-id,然后在客户端检查来破解它,或者有更简单的方法吗?
这里是一个更完整的答案,关于从0.9改变了什么。X到1.x。
// send to current request socket client
socket.emit('message', "this is a test");// Hasn't changed
// sending to all clients, include sender
io.sockets.emit('message', "this is a test"); // Old way, still compatible
io.emit('message', 'this is a test');// New way, works only in 1.x
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");// Hasn't changed
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');// Hasn't changed
// sending to all clients in 'game' room(channel), include sender
io.sockets.in('game').emit('message', 'cool game');// Old way, DOES NOT WORK ANYMORE
io.in('game').emit('message', 'cool game');// New way
io.to('game').emit('message', 'cool game');// New way, "in" or "to" are the exact same: "And then simply use to or in (they are the same) when broadcasting or emitting:" from http://socket.io/docs/rooms-and-namespaces/
// sending to individual socketid, socketid is like a room
io.sockets.socket(socketid).emit('message', 'for your eyes only');// Old way, DOES NOT WORK ANYMORE
socket.broadcast.to(socketid).emit('message', 'for your eyes only');// New way
我想编辑@soyuka的帖子,但我的编辑被同行评审拒绝了。
来自@LearnRPG的答案,但带有1.0:
// send to current request socket client
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.sockets.emit('message', "this is a test"); //still works
//or
io.emit('message', 'this is a test');
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
// docs says "simply use to or in when broadcasting or emitting"
io.in('game').emit('message', 'cool game');
// sending to individual socketid, socketid is like a room
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
为了回答@Crashalot的评论,socketid来自:
var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })
以下是我的列表(1.0版本更新):
// sending to sender-client only
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.emit('message', "this is a test");
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');
// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');
// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');
// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
// list socketid
for (var socketid in io.sockets.sockets) {}
OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});