要向所有客户端发送内容，您可以使用:
io.sockets.emit('response', data);
要接收来自客户的信息，您可以使用:
socket.on('cursor', function(data) {
...
});
如何将这两者结合起来，以便在服务器上从客户端接收消息时，将该消息发送给除发送消息的用户之外的所有用户?
socket.on('cursor', function(data) {
io.sockets.emit('response', data);
});
我是否必须通过发送带有消息的client-id，然后在客户端检查来破解它，或者有更简单的方法吗?
当前回答
来自@LearnRPG的答案，但带有1.0:
// send to current request socket client
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.sockets.emit('message', "this is a test"); //still works
//or
io.emit('message', 'this is a test');
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
// docs says "simply use to or in when broadcasting or emitting"
io.in('game').emit('message', 'cool game');
// sending to individual socketid, socketid is like a room
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
为了回答@Crashalot的评论，socketid来自:
var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })
其他回答
使用这个编码
io.sockets.on('connection', function (socket) {
socket.on('mousemove', function (data) {
socket.broadcast.emit('moving', data);
});
这个socket.broadcast.emit()将发送函数中的所有内容，除了发送到发送的服务器
已为Socket更新。io v4.0.0 +
要发送到除v4中的sender外的所有客户端，您可以使用:
socket.broadcast.emit(/* ... */);
示例使用
io.on("connection", (socket) => {
socket.on("message", (message) => {
//sends "newMessage" to all sockets except sender
socket.broadcast.emit("newMessage", message)
})
})
对于房间中的命名空间，循环房间中的客户端列表(类似于Nav的回答)是我发现的两种可行的方法之一。另一种是使用排除。如
socket.on('message',function(data) {
io.of( 'namespace' ).in( data.roomID ).except( socket.id ).emit('message',data);
}
来自@LearnRPG的答案，但带有1.0:
// send to current request socket client
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.sockets.emit('message', "this is a test"); //still works
//or
io.emit('message', 'this is a test');
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
// docs says "simply use to or in when broadcasting or emitting"
io.in('game').emit('message', 'cool game');
// sending to individual socketid, socketid is like a room
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
为了回答@Crashalot的评论，socketid来自:
var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })
以下是我的列表(1.0版本更新):
// sending to sender-client only
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.emit('message', "this is a test");
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');
// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');
// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');
// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
// list socketid
for (var socketid in io.sockets.sockets) {}
OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});
