还有更好的方法来用jUnit编写吗
String x = "foo bar";
Assert.assertTrue(x.contains("foo"));
还有更好的方法来用jUnit编写吗
String x = "foo bar";
Assert.assertTrue(x.contains("foo"));
当前回答
另一种变体是
Assert.assertThat(actual, new Matches(expectedRegex));
此外,在org.mockito.internal.matchers中还有一些其他有趣的匹配器,如StartWith, Contains等。
其他回答
assertj变体
import org.assertj.core.api.Assertions;
Assertions.assertThat(actualStr).contains(subStr);
如果你添加Hamcrest和JUnit4,你可以这样做:
String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));
使用一些静态导入,它看起来好多了:
assertThat(x, containsString("foo"));
所需的静态导入是:
import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;
另一种变体是
Assert.assertThat(actual, new Matches(expectedRegex));
此外,在org.mockito.internal.matchers中还有一些其他有趣的匹配器,如StartWith, Contains等。
示例(junit版本- 4.13)
import static org.assertj.core.api.Assertions.assertThat;
import org.junit.Test;
public class TestStr {
@Test
public void testThatStringIsContained(){
String testStr = "hi,i am a test string";
assertThat(testStr).contains("test");
}
}
我写了这个效用法
public static void assertContains(String string, String subString) {
Assertions.assertTrue(string.contains(subString));
}