还有更好的方法来用jUnit编写吗

String x = "foo bar";
Assert.assertTrue(x.contains("foo"));

当前回答

如果你添加Hamcrest和JUnit4,你可以这样做:

String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));

使用一些静态导入,它看起来好多了:

assertThat(x, containsString("foo"));

所需的静态导入是:

import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;

其他回答

assertj变体

import org.assertj.core.api.Assertions;
Assertions.assertThat(actualStr).contains(subStr);

EDIT: assertj可能有更多断言(一个fork)

assertThat(x).contains("foo");

另一种变体是

Assert.assertThat(actual, new Matches(expectedRegex));

此外,在org.mockito.internal.matchers中还有一些其他有趣的匹配器,如StartWith, Contains等。

如果你添加Hamcrest和JUnit4,你可以这样做:

String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));

使用一些静态导入,它看起来好多了:

assertThat(x, containsString("foo"));

所需的静态导入是:

import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;

使用hamcrest Matcher containsString()

// Hamcrest assertion
assertThat(person.getName(), containsString("myName"));

// Error Message
java.lang.AssertionError:
Expected: a string containing "myName"
     got: "some other name"

您可以选择添加更详细的错误消息。

// Hamcrest assertion with custom error message
assertThat("my error message", person.getName(), containsString("myName"));

// Error Message
java.lang.AssertionError: my error message
Expected: a string containing "myName"
     got: "some other name"

把我对一个重复问题的答案贴在这里