String paddedString = org.apache.commons.lang.StringUtils.leftPad("129018", 10, "0")

第二个参数是期望的输出长度

"0"是填充字符

我更喜欢这样的代码:

public final class StrMgr {

    public static String rightPad(String input, int length, String fill){                   
        String pad = input.trim() + String.format("%"+length+"s", "").replace(" ", fill);
        return pad.substring(0, length);              
    }       

    public static String leftPad(String input, int length, String fill){            
        String pad = String.format("%"+length+"s", "").replace(" ", fill) + input.trim();
        return pad.substring(pad.length() - length, pad.length());
    }
}

然后:

System.out.println(StrMgr.leftPad("hello", 20, "x")); 
System.out.println(StrMgr.rightPad("hello", 20, "x"));

这是另一种方法:

int pad = 4;
char[] temp = (new String(new char[pad]) + "129018").toCharArray()
Arrays.fill(temp, 0, pad, '0');
System.out.println(temp)

我用过这个:

DecimalFormat numFormat = new DecimalFormat("00000");
System.out.println("Code format: "+numFormat.format(123));

结果:00123

我希望它对你有用!

String str = "129018";
String str2 = String.format("%10s", str).replace(' ', '0');
System.out.println(str2);

基于@Haroldo Macêdo的回答，我在自定义Utils类中创建了一个方法，例如

/**
 * Left padding a string with the given character
 *
 * @param str     The string to be padded
 * @param length  The total fix length of the string
 * @param padChar The pad character
 * @return The padded string
 */
public static String padLeft(String str, int length, String padChar) {
    String pad = "";
    for (int i = 0; i < length; i++) {
        pad += padChar;
    }
    return pad.substring(str.length()) + str;
}

然后打电话给Utils。padLeft(str, 10， "0");