Swift的协议和函数式编程让这变得非常简单，你只需要让你的类符合Comparable协议，实现协议所需的方法，然后使用sorted(by:)高阶函数来创建一个排序的数组，而不需要使用可变数组。

class Person: Comparable {
    var birthDate: NSDate?
    let name: String

    init(name: String) {
        self.name = name
    }

    static func ==(lhs: Person, rhs: Person) -> Bool {
        return lhs.birthDate === rhs.birthDate || lhs.birthDate?.compare(rhs.birthDate as! Date) == .orderedSame
    }

    static func <(lhs: Person, rhs: Person) -> Bool {
        return lhs.birthDate?.compare(rhs.birthDate as! Date) == .orderedAscending
    }

    static func >(lhs: Person, rhs: Person) -> Bool {
        return lhs.birthDate?.compare(rhs.birthDate as! Date) == .orderedDescending
    }

}

let p1 = Person(name: "Sasha")
p1.birthDate = NSDate() 

let p2 = Person(name: "James")
p2.birthDate = NSDate()//he is older by miliseconds

if p1 == p2 {
    print("they are the same") //they are not
}

let persons = [p1, p2]

//sort the array based on who is older
let sortedPersons = persons.sorted(by: {$0 > $1})

//print sasha which is p1
print(persons.first?.name)
//print James which is the "older"
print(sortedPersons.first?.name)

我只是根据自定义需求做了多级排序。

//对值排序

    [arrItem sortUsingComparator:^NSComparisonResult (id a, id b){

    ItemDetail * itemA = (ItemDetail*)a;
    ItemDetail* itemB =(ItemDetail*)b;

    //item price are same
    if (itemA.m_price.m_selling== itemB.m_price.m_selling) {

        NSComparisonResult result=  [itemA.m_itemName compare:itemB.m_itemName];

        //if item names are same, then monogramminginfo has to come before the non monograme item
        if (result==NSOrderedSame) {

            if (itemA.m_monogrammingInfo) {
                return NSOrderedAscending;
            }else{
                return NSOrderedDescending;
            }
        }
        return result;
    }

    //asscending order
    return itemA.m_price.m_selling > itemB.m_price.m_selling;
}];

https://sites.google.com/site/greateindiaclub/mobil-apps/ios/multilevelsortinginiosobjectivec

Swift版本:5.1

如果您有一个自定义结构或类，并希望对它们进行任意排序，您应该调用sort()，使用一个尾随闭包对指定的字段进行排序。下面是一个使用自定义结构数组的例子，该数组根据特定的属性进行排序:

    struct User {
        var firstName: String
    }

    var users = [
        User(firstName: "Jemima"),
        User(firstName: "Peter"),
        User(firstName: "David"),
        User(firstName: "Kelly"),
        User(firstName: "Isabella")
    ]

    users.sort {
        $0.firstName < $1.firstName
    }

如果你想返回一个排序后的数组，而不是原地排序，可以像这样使用sorted():

    let sortedUsers = users.sorted {
        $0.firstName < $1.firstName
    }

您可以使用以下通用方法来实现您的目的。这应该能解决你的问题。

//Called method
-(NSMutableArray*)sortArrayList:(NSMutableArray*)arrDeviceList filterKeyName:(NSString*)sortKeyName ascending:(BOOL)isAscending{
    NSSortDescriptor *sorter = [[NSSortDescriptor alloc] initWithKey:sortKeyName ascending:isAscending];
    [arrDeviceList sortUsingDescriptors:[NSArray arrayWithObject:sorter]];
    return arrDeviceList;
}

//Calling method
[self sortArrayList:arrSomeList filterKeyName:@"anything like date,name etc" ascending:YES];

对于NSMutableArray，使用sortUsingSelector方法。它对位置进行排序，而不创建新实例。

我在iOS 4中使用了block。 必须将数组的元素从id转换为类类型。 在本例中，它是一个名为Score的类，其属性为points。

此外，你需要决定做什么，如果你的数组的元素不是正确的类型，对于这个例子，我只是返回NSOrderedSame，但在我的代码中，我虽然一个异常。

NSArray *sorted = [_scores sortedArrayUsingComparator:^(id obj1, id obj2){
    if ([obj1 isKindOfClass:[Score class]] && [obj2 isKindOfClass:[Score class]]) {
        Score *s1 = obj1;
        Score *s2 = obj2;

        if (s1.points > s2.points) {
            return (NSComparisonResult)NSOrderedAscending;
        } else if (s1.points < s2.points) {
            return (NSComparisonResult)NSOrderedDescending;
        }
    }

    // TODO: default is the same?
    return (NSComparisonResult)NSOrderedSame;
}];

return sorted;

PS:这是降序排序。