在C语言中，整数(对于32位机器)是32位，范围从-32768到+32767。

错，32位有符号整数在2的补式表示中的范围是-231到231-1，等于-2,147,483,648到2,147,483,647。

在C语言中，__int32的范围是-2147483648到2147483647。看这里的全范围。

unsigned short 0 to 65535
signed short –32768 to 32767
unsigned long 0 to 4294967295
signed long –2147483648 to 2147483647

不能保证'int'将是32位，如果你想使用特定大小的变量，特别是在编写涉及位操作的代码时，你应该使用'标准整数类型'。

在Java中

int数据类型是一个32位有符号的二补整数。它的最小值为-2,147,483,648，最大值为2,147,483,647(含)。

32位整数，取值范围为- 2147,483,648 ~ 2147,483,647。然而，你在32位机器上的事实并不意味着你的C编译器使用32位整数。

It is actually really simple to understand, you can even compute it with the google calculator: you have 32 bits for an int and computers are binary, therefore you can have 2 values per bit (spot). if you compute 2^32 you will get the 4,294,967,296. so if you divide this number by 2, (because half of them are negative integers and the other half are positive), then you get 2,147,483,648. and this number is the biggest int that can be represented by 32 bits, although if you pay attention you will notice that 2,147,483,648 is greater than 2,147,483,647 by 1, this is because one of the numbers represents 0 which is right in the middle unfortunately 2^32 is not an odd number therefore you dont have only one number in the middle, so the possitive integers have one less cipher while the negatives get the complete half 2,147,483,648.

就是这样。这取决于机器，而不是语言。

java int的严格等效是C中的long int。

编辑: 如果定义了int32_t，那么它在精度方面是等效的。长整型保证了Java整型的精度，因为它的大小保证至少为32位。

实际上，int的长度(以比特为单位)取决于编译器的实现。

例如，在我的Ubuntu 64位上，我有32位的短，而在另一个32位的Ubuntu版本上，它是16位的。