我能够用time.strptime解析包含日期/时间的字符串
>>> import time
>>> time.strptime('30/03/09 16:31:32', '%d/%m/%y %H:%M:%S')
(2009, 3, 30, 16, 31, 32, 0, 89, -1)
如何解析包含毫秒的时间字符串?
>>> time.strptime('30/03/09 16:31:32.123', '%d/%m/%y %H:%M:%S')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.5/_strptime.py", line 333, in strptime
data_string[found.end():])
ValueError: unconverted data remains: .123
当前回答
对于python 2，我这样做
print ( time.strftime("%H:%M:%S", time.localtime(time.time())) + "." + str(time.time()).split(".",1)[1])
它输出时间“%H:%M:%S”，将time.time()分割为两个子字符串(在。之前和之后)xxxxxxx。由于.xx是我的毫秒，我将第二个子字符串添加到我的“%H:%M:%S”
希望这是有意义的:) 示例输出:
13:31:21.72 眨眼01
13:31:21.81 眨眼结束01
13:31:26.3 眨眼01
13:31:26.39 眨眼结束01
13:31:34.65 01起跑道
其他回答
我知道这是一个老问题，但我仍然在使用Python 2.4.3，我需要找到一种更好的方法将数据字符串转换为日期时间。
如果datetime不支持%f并且不需要try/except，解决方案是:
(dt, mSecs) = row[5].strip().split(".")
dt = datetime.datetime(*time.strptime(dt, "%Y-%m-%d %H:%M:%S")[0:6])
mSeconds = datetime.timedelta(microseconds = int(mSecs))
fullDateTime = dt + mSeconds
这适用于输入字符串“2010-10-06 09:42:52.266000”
Python 2.6添加了新的strftime/strptime宏%f。文档中只提到了微秒，这有点误导人，但%f实际上解析秒的任何小数部分，最多有6位，这意味着它也适用于毫秒，甚至厘秒或分秒。
time.strptime('30/03/09 16:31:32.123', '%d/%m/%y %H:%M:%S.%f')
然而,时间。Struct_time实际上并不存储毫秒/微秒。你最好使用datetime，像这样:
>>> from datetime import datetime
>>> a = datetime.strptime('30/03/09 16:31:32.123', '%d/%m/%y %H:%M:%S.%f')
>>> a.microsecond
123000
如您所见，.123被正确地解释为123000微秒。
对于python 2，我这样做
print ( time.strftime("%H:%M:%S", time.localtime(time.time())) + "." + str(time.time()).split(".",1)[1])
它输出时间“%H:%M:%S”，将time.time()分割为两个子字符串(在。之前和之后)xxxxxxx。由于.xx是我的毫秒，我将第二个子字符串添加到我的“%H:%M:%S”
希望这是有意义的:) 示例输出:
13:31:21.72 眨眼01
13:31:21.81 眨眼结束01
13:31:26.3 眨眼01
13:31:26.39 眨眼结束01
13:31:34.65 01起跑道
给出nstehr的答案所引用的代码(来自它的源代码):
def timeparse(t, format):
"""Parse a time string that might contain fractions of a second.
Fractional seconds are supported using a fragile, miserable hack.
Given a time string like '02:03:04.234234' and a format string of
'%H:%M:%S', time.strptime() will raise a ValueError with this
message: 'unconverted data remains: .234234'. If %S is in the
format string and the ValueError matches as above, a datetime
object will be created from the part that matches and the
microseconds in the time string.
"""
try:
return datetime.datetime(*time.strptime(t, format)[0:6]).time()
except ValueError, msg:
if "%S" in format:
msg = str(msg)
mat = re.match(r"unconverted data remains:"
" \.([0-9]{1,6})$", msg)
if mat is not None:
# fractional seconds are present - this is the style
# used by datetime's isoformat() method
frac = "." + mat.group(1)
t = t[:-len(frac)]
t = datetime.datetime(*time.strptime(t, format)[0:6])
microsecond = int(float(frac)*1e6)
return t.replace(microsecond=microsecond)
else:
mat = re.match(r"unconverted data remains:"
" \,([0-9]{3,3})$", msg)
if mat is not None:
# fractional seconds are present - this is the style
# used by the logging module
frac = "." + mat.group(1)
t = t[:-len(frac)]
t = datetime.datetime(*time.strptime(t, format)[0:6])
microsecond = int(float(frac)*1e6)
return t.replace(microsecond=microsecond)
raise
来自python邮件列表:解析毫秒线程。有一个函数张贴在那里，似乎可以完成这项工作，尽管正如作者的评论中提到的，这是一种hack。它使用正则表达式来处理引发的异常，然后进行一些计算。
您还可以在将正则表达式传递给strptime之前，尝试预先执行正则表达式和计算。
