这是我的HTML表单:
<form name="myForm" ng-submit="">
<input ng-model='file' type="file"/>
<input type="submit" value='Submit'/>
</form>
我想从本地机器上传一个图像，并想读取上传文件的内容。所有这些我都想用AngularJS来做。
当我试图打印$scope的值时。文件是未定义的。
当前回答
app.directive('ngUpload', function () {
return {
restrict: 'A',
link: function (scope, element, attrs) {
var options = {};
options.enableControls = attrs['uploadOptionsEnableControls'];
// get scope function to execute on successful form upload
if (attrs['ngUpload']) {
element.attr("target", "upload_iframe");
element.attr("method", "post");
// Append a timestamp field to the url to prevent browser caching results
element.attr("action", element.attr("action") + "?_t=" + new Date().getTime());
element.attr("enctype", "multipart/form-data");
element.attr("encoding", "multipart/form-data");
// Retrieve the callback function
var fn = attrs['ngUpload'].split('(')[0];
var callbackFn = scope.$eval(fn);
if (callbackFn == null || callbackFn == undefined || !angular.isFunction(callbackFn))
{
var message = "The expression on the ngUpload directive does not point to a valid function.";
// console.error(message);
throw message + "\n";
}
// Helper function to create new i frame for each form submission
var addNewDisposableIframe = function (submitControl) {
// create a new iframe
var iframe = $("<iframe id='upload_iframe' name='upload_iframe' border='0' width='0' height='0' style='width: 0px; height: 0px;
border: none; display: none' />");
// attach function to load event of the iframe
iframe.bind('load', function () {
// get content - requires jQuery
var content = iframe.contents().find('body').text();
// execute the upload response function in the active scope
scope.$apply(function () { callbackFn(content, content !== "" /* upload completed */); });
// remove iframe
if (content != "") // Fixes a bug in Google Chrome that dispose the iframe before content is ready.
setTimeout(function () { iframe.remove(); }, 250);
submitControl.attr('disabled', null);
submitControl.attr('title', 'Click to start upload.');
});
// add the new iframe to application
element.parent().append(iframe);
};
// 1) get the upload submit control(s) on the form (submitters must be decorated with the 'ng-upload-submit' class)
// 2) attach a handler to the controls' click event
$('.upload-submit', element).click(
function () {
addNewDisposableIframe($(this) /* pass the submit control */);
scope.$apply(function () { callbackFn("Please wait...", false /* upload not completed */); });
var enabled = true;
if (options.enableControls === null || options.enableControls === undefined || options.enableControls.length >= 0) {
// disable the submit control on click
$(this).attr('disabled', 'disabled');
enabled = false;
}
$(this).attr('title', (enabled ? '[ENABLED]: ' : '[DISABLED]: ') + 'Uploading, please wait...');
// submit the form
$(element).submit();
}
).attr('title', 'Click to start upload.');
}
else
alert("No callback function found on the ngUpload directive.");
}
};
});
<form class="form form-inline" name="uploadForm" id="uploadForm"
ng-upload="uploadForm12" action="rest/uploadHelpFile" method="post"
enctype="multipart/form-data" style="margin-top: 3px;margin-left:
6px"> <button type="submit" id="mbUploadBtn" class="upload-submit"
ng-hide="true"></button> </form>
@RequestMapping(value = "/uploadHelpFile", method =
RequestMethod.POST) public @ResponseBody String
uploadHelpFile(@RequestParam(value = "file") CommonsMultipartFile[]
file,@RequestParam(value = "fileName") String
fileName,@RequestParam(value = "helpFileType") String
helpFileType,@RequestParam(value = "helpFileName") String
helpFileName) { }
其他回答
使用简单指令的示例(ng-file-model):
.directive("ngFileModel", [function () {
return {
$scope: {
ngFileModel: "="
},
link: function ($scope:any, element, attributes) {
element.bind("change", function (changeEvent:any) {
var reader = new FileReader();
reader.onload = function (loadEvent) {
$scope.$apply(function () {
$scope.ngFileModel = {
lastModified: changeEvent.target.files[0].lastModified,
lastModifiedDate: changeEvent.target.files[0].lastModifiedDate,
name: changeEvent.target.files[0].name,
size: changeEvent.target.files[0].size,
type: changeEvent.target.files[0].type,
data: changeEvent.target.files[0]
};
});
}
reader.readAsDataURL(changeEvent.target.files[0]);
});
}
}
}])
并使用FormData在函数中上传文件。
var formData = new FormData();
formData.append("document", $scope.ngFileModel.data)
formData.append("user_id", $scope.userId)
所有学分都归 https://github.com/mistralworks/ng-file-model
我遇到了一个小问题，你可以在这里查看: https://github.com/mistralworks/ng-file-model/issues/7
最后，这里是一个分叉的回购:https://github.com/okasha93/ng-file-model/blob/patch-1/ng-file-model.js
HTML
<html>
<head></head>
<body ng-app = "myApp">
<form ng-controller = "myCtrl">
<input type = "file" file-model="files" multiple/>
<button ng-click = "uploadFile()">upload me</button>
<li ng-repeat="file in files">{{file.name}}</li>
</form>
脚本
<script src =
"http://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
<script>
angular.module('myApp', []).directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
element.bind('change', function(){
$parse(attrs.fileModel).assign(scope,element[0].files)
scope.$apply();
});
}
};
}]).controller('myCtrl', ['$scope', '$http', function($scope, $http){
$scope.uploadFile=function(){
var fd=new FormData();
console.log($scope.files);
angular.forEach($scope.files,function(file){
fd.append('file',file);
});
$http.post('http://localhost:1337/mediaobject/upload',fd,
{
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).success(function(d)
{
console.log(d);
})
}
}]);
</script>
使用onchange事件将输入文件元素传递给函数。
<输入类型=“文件”/>
因此，当用户选择一个文件时，您就有了对该文件的引用，而不需要用户单击“添加”或“上传”按钮。
$scope.fileSelected = function (element) {
var myFileSelected = element.files[0];
};
这里的一些答案建议使用FormData()，但不幸的是，这是一个浏览器对象，在Internet Explorer 9及以下版本中不可用。如果您需要支持这些旧浏览器，您将需要一个备份策略，例如使用<iframe>或Flash。
已经有很多Angular.js模块来执行文件上传。这两种浏览器都明确支持旧浏览器:
https://github.com/leon/angular-upload -使用iframes作为备份 https://github.com/danialfarid/ng-file-upload -使用FileAPI/Flash作为备份
还有一些其他的选择:
https://github.com/nervgh/angular-file-upload/ https://github.com/uor/angular-file https://github.com/twilson63/ngUpload https://github.com/uploadcare/angular-uploadcare
其中一个应该适合你的项目，或者可能会给你一些关于如何自己编写代码的见解。
该代码将帮助插入文件
<body ng-app = "myApp">
<form ng-controller="insert_Ctrl" method="post" action="" name="myForm" enctype="multipart/form-data" novalidate>
<div>
<p><input type="file" ng-model="myFile" class="form-control" onchange="angular.element(this).scope().uploadedFile(this)">
<span style="color:red" ng-show="(myForm.myFile.$error.required&&myForm.myFile.$touched)">Select Picture</span>
</p>
</div>
<div>
<input type="button" name="submit" ng-click="uploadFile()" class="btn-primary" ng-disabled="myForm.myFile.$invalid" value="insert">
</div>
</form>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script>
<script src="insert.js"></script>
</body>
insert.js
var app = angular.module('myApp',[]);
app.service('uploadFile', ['$http','$window', function ($http,$window) {
this.uploadFiletoServer = function(file,uploadUrl){
var fd = new FormData();
fd.append('file', file);
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(data){
alert("insert successfull");
$window.location.href = ' ';//your window location
})
.error(function(){
alert("Error");
});
}
}]);
app.controller('insert_Ctrl', ['$scope', 'uploadFile', function($scope, uploadFile){
$scope.uploadFile = function() {
$scope.myFile = $scope.files[0];
var file = $scope.myFile;
var url = "save_data.php";
uploadFile.uploadFiletoServer(file,url);
};
$scope.uploadedFile = function(element) {
var reader = new FileReader();
reader.onload = function(event) {
$scope.$apply(function($scope) {
$scope.files = element.files;
$scope.src = event.target.result
});
}
reader.readAsDataURL(element.files[0]);
}
}]);
save_data.php
<?php
require "dbconnection.php";
$ext = pathinfo($_FILES['file']['name'],PATHINFO_EXTENSION);
$image = time().'.'.$ext;
move_uploaded_file($_FILES["file"]["tmp_name"],"upload/".$image);
$query="insert into test_table values ('null','$image')";
mysqli_query($con,$query);
?>
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