Glue是作为tidyverse的一部分开发的一个新函数、数据类和包，具有许多扩展功能。它结合了paste、sprintf和前面其他答案的特性。

tmp <- tibble::tibble(firststring = "GAD", secondstring = "AB")
(tmp_new <- glue::glue_data(tmp, "{firststring},{secondstring}"))
#> GAD,AB

由reprex包于2019-03-06创建(v0.2.1)

是的，对于这个问题中的简单例子来说，它有点过头了，但在许多情况下都很强大。(参见https://glue.tidyverse.org/)

快速的例子比较粘贴与下面。胶水代码更容易输入，看起来也更容易阅读。

tmp <- tibble::tibble(firststring = c("GAD", "GAD2", "GAD3"), secondstring = c("AB1", "AB2", "AB3"))
(tmp_new <- glue::glue_data(tmp, "{firststring} and {secondstring} went to the park for a walk. {firststring} forgot his keys."))
#> GAD and AB1 went to the park for a walk. GAD forgot his keys.
#> GAD2 and AB2 went to the park for a walk. GAD2 forgot his keys.
#> GAD3 and AB3 went to the park for a walk. GAD3 forgot his keys.
(with(tmp, paste(firststring, "and", secondstring, "went to the park for a walk.", firststring, "forgot his keys.")))
#> [1] "GAD and AB1 went to the park for a walk. GAD forgot his keys."  
#> [2] "GAD2 and AB2 went to the park for a walk. GAD2 forgot his keys."
#> [3] "GAD3 and AB3 went to the park for a walk. GAD3 forgot his keys."

由reprex包于2019-03-06创建(v0.2.1)

考虑这样一种情况，字符串是列，结果应该是一个新列:

df <- data.frame(a = letters[1:5], b = LETTERS[1:5], c = 1:5)

df$new_col <- do.call(paste, c(df[c("a", "b")], sep = ", ")) 
df
#  a b c new_col
#1 a A 1    a, A
#2 b B 2    b, B
#3 c C 3    c, C
#4 d D 4    d, D
#5 e E 5    e, E

如果需要粘贴所有列，可以跳过[c("a"， "b")]子设置。

# you can also try str_c from stringr package as mentioned by other users too!
do.call(str_c, c(df[c("a", "b")], sep = ", ")) 

正如其他人所指出的，paste()是正确的方法。但是每次需要使用非默认分隔符时，都必须输入paste(str1, str2, str3, sep= ")，这很烦人。

您可以非常容易地创建包装器函数，使工作变得更加简单。例如，如果你发现自己经常连接没有分隔符的字符串，你可以这样做:

p <- function(..., sep='') {
    paste(..., sep=sep, collapse=sep)
}

或者如果你经常想从一个向量连接字符串(比如PHP中的implode()):

implode <- function(..., sep='') {
     paste(..., collapse=sep)
}

允许你这样做:

p('a', 'b', 'c')
#[1] "abc"
vec <- c('a', 'b', 'c')
implode(vec)
#[1] "abc"
implode(vec, sep=', ')
#[1] "a, b, c"

此外，还有内置的paste0，它做的事情与我的implode相同，但不允许自定义分隔符。它比paste()稍微高效一些。

给定你创建的矩阵tmp:

paste(tmp[1,], collapse = ",")

我假设有一些原因，为什么你创建一个矩阵使用cbind，而不是简单地:

tmp <- "GAD,AB"

Glue是作为tidyverse的一部分开发的一个新函数、数据类和包，具有许多扩展功能。它结合了paste、sprintf和前面其他答案的特性。

tmp <- tibble::tibble(firststring = "GAD", secondstring = "AB")
(tmp_new <- glue::glue_data(tmp, "{firststring},{secondstring}"))
#> GAD,AB

由reprex包于2019-03-06创建(v0.2.1)

是的，对于这个问题中的简单例子来说，它有点过头了，但在许多情况下都很强大。(参见https://glue.tidyverse.org/)

快速的例子比较粘贴与下面。胶水代码更容易输入，看起来也更容易阅读。

tmp <- tibble::tibble(firststring = c("GAD", "GAD2", "GAD3"), secondstring = c("AB1", "AB2", "AB3"))
(tmp_new <- glue::glue_data(tmp, "{firststring} and {secondstring} went to the park for a walk. {firststring} forgot his keys."))
#> GAD and AB1 went to the park for a walk. GAD forgot his keys.
#> GAD2 and AB2 went to the park for a walk. GAD2 forgot his keys.
#> GAD3 and AB3 went to the park for a walk. GAD3 forgot his keys.
(with(tmp, paste(firststring, "and", secondstring, "went to the park for a walk.", firststring, "forgot his keys.")))
#> [1] "GAD and AB1 went to the park for a walk. GAD forgot his keys."  
#> [2] "GAD2 and AB2 went to the park for a walk. GAD2 forgot his keys."
#> [3] "GAD3 and AB3 went to the park for a walk. GAD3 forgot his keys."

由reprex包于2019-03-06创建(v0.2.1)

你可以创建自己的操作符:

'%&%' <- function(x, y)paste0(x,y)
"new" %&% "operator"
[1] newoperator`

你也可以重新定义'and'(&)操作符:

'&' <- function(x, y)paste0(x,y)
"dirty" & "trick"
"dirtytrick"

混淆基线语法是丑陋的，但是使用paste()/paste0()也是如此，如果你只使用自己的代码，你可以(几乎总是)将逻辑&和操作符替换为*，并执行逻辑值的乘法，而不是使用逻辑'and '