我正在运行一个服务器,我想显示我自己的IP地址。

获取计算机自身(如果可能的话,外部)IP地址的语法是什么?

有人编写了以下代码。

IPHostEntry host;
string localIP = "?";
host = Dns.GetHostEntry(Dns.GetHostName());
foreach (IPAddress ip in host.AddressList)
{
    if (ip.AddressFamily.ToString() == "InterNetwork")
    {
        localIP = ip.ToString();
    }
}
return localIP;

然而,我通常不信任作者,我不理解这段代码。有更好的方法吗?


当前回答

如果你在内部网络中运行,你将能够获得本地机器的IP地址,如果不是,你将获得外部IP地址: 网络:

//this will bring the IP for the current machine on browser
System.Web.HttpContext.Current.Request.UserHostAddress

桌面:

//This one will bring all local IPs for the desired namespace
IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());

其他回答

试试这个:

 IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());
 String MyIp = localIPs[0].ToString();
namespace NKUtilities 
{
    using System;
    using System.Net;
    using System.Net.Sockets;

    public class DNSUtility
    {
        public static int Main(string [] args)
        {
            string strHostName = "";
            try {

                if(args.Length == 0)
                {
                    // Getting Ip address of local machine...
                    // First get the host name of local machine.
                    strHostName = Dns.GetHostName();
                    Console.WriteLine ("Local Machine's Host Name: " +  strHostName);
                }
                else
                {
                    // Otherwise, get the IP address of the host provided on the command line.
                    strHostName = args[0];
                }

                // Then using host name, get the IP address list..
                IPHostEntry ipEntry = Dns.GetHostEntry (strHostName);
                IPAddress [] addr = ipEntry.AddressList;

                for(int i = 0; i < addr.Length; i++)
                {
                    Console.WriteLine("IP Address {0}: {1} ", i, addr[i].ToString());
                }
                return 0;

            } 
            catch(SocketException se) 
            {
                Console.WriteLine("{0} ({1})", se.Message, strHostName);
                return -1;
            } 
            catch(Exception ex) 
            {
                Console.WriteLine("Error: {0}.", ex.Message);
                return -1;
            }
        }
    }
}

详情请看这里。

你必须记住你的电脑可以有多个IP(实际上它总是这样)-所以你是哪一个。

这是我解决它的方法。我知道如果你有几个物理接口,这可能不会选择你想要的确切的eth。

private string FetchIP()
{
    //Get all IP registered
    List<string> IPList = new List<string>();
    IPHostEntry host;
    host = Dns.GetHostEntry(Dns.GetHostName());
    foreach (IPAddress ip in host.AddressList)
    {
        if (ip.AddressFamily == AddressFamily.InterNetwork)
        {
            IPList.Add(ip.ToString());
        }
    }

    //Find the first IP which is not only local
    foreach (string a in IPList)
    {
        Ping p = new Ping();
        string[] b = a.Split('.');
        string ip2 = b[0] + "." + b[1] + "." + b[2] + ".1";
        PingReply t = p.Send(ip2);
        p.Dispose();
        if (t.Status == IPStatus.Success && ip2 != a)
        {
            return a;
        }
    }
    return null;
}

以最快的方式获取远程ip地址。您必须使用下载程序,或者在您的计算机上创建一个服务器。

使用这段简单代码的缺点:(这是推荐的)是它将花费3-5秒来获取您的远程IP地址,因为web客户端初始化时总是需要3-5秒来检查您的代理设置。

 public static string GetIP()
 {
            string externalIP = "";
            externalIP = new WebClient().DownloadString("http://checkip.dyndns.org/");
            externalIP = (new Regex(@"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}"))
                                           .Matches(externalIP)[0].ToString();
            return externalIP;
 }

这是我如何修复它..(第一次仍然需要3-5秒),但在那之后,它总是会在0-2秒内得到你的远程IP地址,这取决于你的连接。

public static WebClient webclient = new WebClient();
public static string GetIP()
{
    string externalIP = "";
    externalIP = webclient.DownloadString("http://checkip.dyndns.org/");
    externalIP = (new Regex(@"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}"))
                                   .Matches(externalIP)[0].ToString();
    return externalIP;
}
WebClient webClient = new WebClient();
string IP = webClient.DownloadString("http://myip.ozymo.com/");