我使用的是Angular 2 (TypeScript)。
我想对新的选择做一些事情，但我在onChange()中得到的总是最后一个选择。我如何获得新的选择?
<select [(ngModel)]="selectedDevice" (change)="onChange($event)">
<option *ngFor="#i of devices">{{i}}</option>
</select>
onChange($event) {
console.log(this.selectedDevice);
// I want to do something here with the new selectedDevice, but what I
// get here is always the last selection, not the one I just selected.
}
当前回答
我也有同样的问题，我用下面的代码解决了:
(change)="onChange($event.target.value)"
其他回答
使用[ngValue]代替[value]!!
export class Organisation {
description: string;
id: string;
name: string;
}
export class ScheduleComponent implements OnInit {
selectedOrg: Organisation;
orgs: Organisation[] = [];
constructor(private organisationService: OrganisationService) {}
get selectedOrgMod() {
return this.selectedOrg;
}
set selectedOrgMod(value) {
this.selectedOrg = value;
}
}
<div class="form-group">
<label for="organisation">Organisation
<select id="organisation" class="form-control" [(ngModel)]="selectedOrgMod" required>
<option *ngFor="let org of orgs" [ngValue]="org">{{org.name}}</option>
</select>
</label>
</div>
在Angular 5中，我是这样做的。获取对象$event。Value而不是$event.target.value
<mat-form-field color="warn">
<mat-select (ngModelChange)="onChangeTown($event)" class="form-width" formControlName="branch" [(ngModel)]="branch" placeholder="Enter branch">
<mat-option *ngFor="let branch of branchs" [value]="branch.value">
{{ branch.name }}
</mat-option>
</mat-select>
</mat-form-field>
onChangeTown(event): void {
const selectedTown = event;
console.log('selectedTown: ', selectedTown);
}
如果你不需要双向数据绑定:
<select (change)="onChange($event.target.value)">
<option *ngFor="let i of devices">{{i}}</option>
</select>
onChange(deviceValue) {
console.log(deviceValue);
}
对于双向数据绑定，分离事件和属性绑定:
<select [ngModel]="selectedDevice" (ngModelChange)="onChange($event)" name="sel2">
<option [value]="i" *ngFor="let i of devices">{{i}}</option>
</select>
export class AppComponent {
devices = 'one two three'.split(' ');
selectedDevice = 'two';
onChange(newValue) {
console.log(newValue);
this.selectedDevice = newValue;
// ... do other stuff here ...
}
如果devices是一个对象数组，绑定到ngValue而不是value:
<select [ngModel]="selectedDeviceObj" (ngModelChange)="onChangeObj($event)" name="sel3">
<option [ngValue]="i" *ngFor="let i of deviceObjects">{{i.name}}</option>
</select>
{{selectedDeviceObj | json}}
export class AppComponent {
deviceObjects = [{name: 1}, {name: 2}, {name: 3}];
selectedDeviceObj = this.deviceObjects[1];
onChangeObj(newObj) {
console.log(newObj);
this.selectedDeviceObj = newObj;
// ... do other stuff here ...
}
}
活塞-不使用<形式> Plunker -使用<form>并使用新的表单API
在Angular 8中，你可以像这样简单地使用"selectionChange":
<mat-select [(value)]="selectedData" (selectionChange)="onChange()" >
<mat-option *ngFor="let i of data" [value]="i.ItemID">
{{i.ItemName}}
</mat-option>
</mat-select>
在angular 6及以上使用selectionChange。例子 (selectionChange) = onChange (event.value美元)
