我使用的是Angular 2 (TypeScript)。
我想对新的选择做一些事情，但我在onChange()中得到的总是最后一个选择。我如何获得新的选择?
<select [(ngModel)]="selectedDevice" (change)="onChange($event)">
<option *ngFor="#i of devices">{{i}}</option>
</select>
onChange($event) {
console.log(this.selectedDevice);
// I want to do something here with the new selectedDevice, but what I
// get here is always the last selection, not the one I just selected.
}
当前回答
如果你不需要双向数据绑定:
<select (change)="onChange($event.target.value)">
<option *ngFor="let i of devices">{{i}}</option>
</select>
onChange(deviceValue) {
console.log(deviceValue);
}
对于双向数据绑定，分离事件和属性绑定:
<select [ngModel]="selectedDevice" (ngModelChange)="onChange($event)" name="sel2">
<option [value]="i" *ngFor="let i of devices">{{i}}</option>
</select>
export class AppComponent {
devices = 'one two three'.split(' ');
selectedDevice = 'two';
onChange(newValue) {
console.log(newValue);
this.selectedDevice = newValue;
// ... do other stuff here ...
}
如果devices是一个对象数组，绑定到ngValue而不是value:
<select [ngModel]="selectedDeviceObj" (ngModelChange)="onChangeObj($event)" name="sel3">
<option [ngValue]="i" *ngFor="let i of deviceObjects">{{i.name}}</option>
</select>
{{selectedDeviceObj | json}}
export class AppComponent {
deviceObjects = [{name: 1}, {name: 2}, {name: 3}];
selectedDeviceObj = this.deviceObjects[1];
onChangeObj(newObj) {
console.log(newObj);
this.selectedDeviceObj = newObj;
// ... do other stuff here ...
}
}
活塞-不使用<形式> Plunker -使用<form>并使用新的表单API
其他回答
如果你不需要双向数据绑定:
<select (change)="updateSorting($event)">
<option disabled selected>Sorting</option>
<option value="pointDes">pointDes</option>
<option value="timeDes">timeDes</option>
<option value="timeAsc">timeAsc</option>
<option value="pointAsc">pointAsc</option>
</select>
updateSorting(e: any) {
// console.log((e.target as HTMLSelectElement)?.value); // also work
console.log(e.target.value);
}
你可以通过在选择标签#device上创建一个引用变量来将值传递回组件，并将它传递给更改处理程序onChange($event, device.value)应该有新值
<select [(ng-model)]="selectedDevice" #device (change)="onChange($event, device.value)">
<option *ng-for="#i of devices">{{i}}</option>
</select>
onChange($event, deviceValue) {
console.log(deviceValue);
}
在Angular 5中，我是这样做的。获取对象$event。Value而不是$event.target.value
<mat-form-field color="warn">
<mat-select (ngModelChange)="onChangeTown($event)" class="form-width" formControlName="branch" [(ngModel)]="branch" placeholder="Enter branch">
<mat-option *ngFor="let branch of branchs" [value]="branch.value">
{{ branch.name }}
</mat-option>
</mat-select>
</mat-form-field>
onChangeTown(event): void {
const selectedTown = event;
console.log('selectedTown: ', selectedTown);
}
在Angular 8中，你可以像这样简单地使用"selectionChange":
<mat-select [(value)]="selectedData" (selectionChange)="onChange()" >
<mat-option *ngFor="let i of data" [value]="i.ItemID">
{{i.ItemName}}
</mat-option>
</mat-select>
如果你不需要双向数据绑定:
<select (change)="onChange($event.target.value)">
<option *ngFor="let i of devices">{{i}}</option>
</select>
onChange(deviceValue) {
console.log(deviceValue);
}
对于双向数据绑定，分离事件和属性绑定:
<select [ngModel]="selectedDevice" (ngModelChange)="onChange($event)" name="sel2">
<option [value]="i" *ngFor="let i of devices">{{i}}</option>
</select>
export class AppComponent {
devices = 'one two three'.split(' ');
selectedDevice = 'two';
onChange(newValue) {
console.log(newValue);
this.selectedDevice = newValue;
// ... do other stuff here ...
}
如果devices是一个对象数组，绑定到ngValue而不是value:
<select [ngModel]="selectedDeviceObj" (ngModelChange)="onChangeObj($event)" name="sel3">
<option [ngValue]="i" *ngFor="let i of deviceObjects">{{i.name}}</option>
</select>
{{selectedDeviceObj | json}}
export class AppComponent {
deviceObjects = [{name: 1}, {name: 2}, {name: 3}];
selectedDeviceObj = this.deviceObjects[1];
onChangeObj(newObj) {
console.log(newObj);
this.selectedDeviceObj = newObj;
// ... do other stuff here ...
}
}
活塞-不使用<形式> Plunker -使用<form>并使用新的表单API
