我使用的是Angular 2 (TypeScript)。

我想对新的选择做一些事情,但我在onChange()中得到的总是最后一个选择。我如何获得新的选择?

<select [(ngModel)]="selectedDevice" (change)="onChange($event)">
   <option *ngFor="#i of devices">{{i}}</option>
</select>
onChange($event) {
    console.log(this.selectedDevice);
    // I want to do something here with the new selectedDevice, but what I
    // get here is always the last selection, not the one I just selected.
}

当前回答

使用[ngValue]代替[value]!!

export class Organisation {
  description: string;
  id: string;
  name: string;
}
export class ScheduleComponent implements OnInit {
  selectedOrg: Organisation;
  orgs: Organisation[] = [];

  constructor(private organisationService: OrganisationService) {}

  get selectedOrgMod() {
    return this.selectedOrg;
  }

  set selectedOrgMod(value) {
    this.selectedOrg = value;
  }
}


<div class="form-group">
      <label for="organisation">Organisation
      <select id="organisation" class="form-control" [(ngModel)]="selectedOrgMod" required>
        <option *ngFor="let org of orgs" [ngValue]="org">{{org.name}}</option>
      </select>
      </label>
</div>

其他回答

另一种选择是将对象的value存储为字符串:

<select [ngModel]="selectedDevice | json" (ngModelChange)="onChange($event)">
    <option [value]="i | json" *ngFor="let i of devices">{{i}}</option>
</select>

组件:

onChange(val) {
    this.selectedDevice = JSON.parse(val);
}

这是唯一的方法,我可以得到双向绑定工作,以设置页面加载的选择值。这是因为填充选择框的列表与我的选择绑定的对象不完全相同,它需要是相同的对象,而不仅仅是相同的属性值。

在Angular 8中,你可以像这样简单地使用"selectionChange":

 <mat-select  [(value)]="selectedData" (selectionChange)="onChange()" >
  <mat-option *ngFor="let i of data" [value]="i.ItemID">
  {{i.ItemName}}
  </mat-option>
 </mat-select>
<mat-form-field>
<mat-select placeholder="Vacancies" [(ngModel)]="vacanciesSpinnerSelectedItem.code" (ngModelChange)="spinnerClick1($event)"
    [ngModelOptions]="{standalone: true}" required>
    <mat-option *ngFor="let spinnerValue of vacanciesSpinnerValues" [value]="spinnerValue?.code">{{spinnerValue.description}}</mat-option>
</mat-select>

我使用这个角材质下拉。工作正常

我也有同样的问题,我用下面的代码解决了:

(change)="onChange($event.target.value)"

如果你不需要双向数据绑定:

<select (change)="onChange($event.target.value)">
    <option *ngFor="let i of devices">{{i}}</option>
</select>

onChange(deviceValue) {
    console.log(deviceValue);
}

对于双向数据绑定,分离事件和属性绑定:

<select [ngModel]="selectedDevice" (ngModelChange)="onChange($event)" name="sel2">
    <option [value]="i" *ngFor="let i of devices">{{i}}</option>
</select>
export class AppComponent {
  devices = 'one two three'.split(' ');
  selectedDevice = 'two';
  onChange(newValue) {
    console.log(newValue);
    this.selectedDevice = newValue;
    // ... do other stuff here ...
}

如果devices是一个对象数组,绑定到ngValue而不是value:

<select [ngModel]="selectedDeviceObj" (ngModelChange)="onChangeObj($event)" name="sel3">
  <option [ngValue]="i" *ngFor="let i of deviceObjects">{{i.name}}</option>
</select>
{{selectedDeviceObj | json}}
export class AppComponent {
  deviceObjects = [{name: 1}, {name: 2}, {name: 3}];
  selectedDeviceObj = this.deviceObjects[1];
  onChangeObj(newObj) {
    console.log(newObj);
    this.selectedDeviceObj = newObj;
    // ... do other stuff here ...
  }
}

活塞-不使用<形式> Plunker -使用<form>并使用新的表单API