我想将这些类型的值“3”、“2.34”、“0.234343”等转换为数字。在JavaScript中,我们可以使用Number(),但在PHP中有没有类似的方法?
Input Output
'2' 2
'2.34' 2.34
'0.3454545' 0.3454545
我想将这些类型的值“3”、“2.34”、“0.234343”等转换为数字。在JavaScript中,我们可以使用Number(),但在PHP中有没有类似的方法?
Input Output
'2' 2
'2.34' 2.34
'0.3454545' 0.3454545
当前回答
如果你事先不知道你有一个浮点数还是一个整数,如果字符串可能包含特殊字符(如空格、欧元等),并且如果它可以包含多于1个点或逗号,您可以使用此功能:
// This function strip spaces and other characters from a string and return a number.
// It works for integer and float.
// It expect decimal delimiter to be either a '.' or ','
// Note: everything after an eventual 2nd decimal delimiter will be removed.
function stringToNumber($string) {
// return 0 if the string contains no number at all or is not a string:
if (!is_string($string) || !preg_match('/\d/', $string)) {
return 0;
}
// Replace all ',' with '.':
$workingString = str_replace(',', '.', $string);
// Keep only number and '.':
$workingString = preg_replace("/[^0-9.]+/", "", $workingString);
// Split the integer part and the decimal part,
// (and eventually a third part if there are more
// than 1 decimal delimiter in the string):
$explodedString = explode('.', $workingString, 3);
if ($explodedString[0] === '') {
// No number was present before the first decimal delimiter,
// so we assume it was meant to be a 0:
$explodedString[0] = '0';
}
if (sizeof($explodedString) === 1) {
// No decimal delimiter was present in the string,
// create a string representing an integer:
$workingString = $explodedString[0];
} else {
// A decimal delimiter was present,
// create a string representing a float:
$workingString = $explodedString[0] . '.' . $explodedString[1];
}
// Create a number from this now non-ambiguous string:
$number = $workingString * 1;
return $number;
}
其他回答
是的,PHP中有一个类似的方法,但它鲜为人知,所以你很少听说它。它是一个叫做“身份”的算术运算符,如下所述:
算术运算符
要将数字字符串转换为数字,请执行以下操作:
$a = +$a;
实现这一目标的多种方式之一是:
$fileDownloadCount = (int) column_data_from_db;
$fileDownloadCount++;
第二行将值递增1。
在某些情况下,只需注意一些有用且安全的答案。您可能需要先检查字符串是否包含有效的数值,然后才能将其转换为数值类型(例如,如果您必须处理来自将int转换为字符串的数据库的数据)。可以使用is_numeric(),然后使用floatval():
$a = "whatever"; // any variable
if (is_numeric($a))
var_dump(floatval($a)); // type is float
else
var_dump($a); // any type
PHP将在限制范围内为您提供
<?php
$str = "3.148";
$num = $str;
printf("%f\n", $num);
?>
在一次编程面试中,我遇到了这样一个问题:“假设你正在编写一个内置函数,用PHP将整数转换为字符串,你会如何编写该函数”。这里有一个解决方案。
$nums = ["0","1","2","3","4","5","6","7","8","9"];
$int = 15939;
$string = "";
while ($int) {
$string .= $nums[$int % 10];
$int = (int)($int / 10);
}
$result = strrev($string);