我想将这些类型的值“3”、“2.34”、“0.234343”等转换为数字。在JavaScript中,我们可以使用Number(),但在PHP中有没有类似的方法?
Input Output
'2' 2
'2.34' 2.34
'0.3454545' 0.3454545
我想将这些类型的值“3”、“2.34”、“0.234343”等转换为数字。在JavaScript中,我们可以使用Number(),但在PHP中有没有类似的方法?
Input Output
'2' 2
'2.34' 2.34
'0.3454545' 0.3454545
当前回答
实现这一目标的多种方式之一是:
$fileDownloadCount = (int) column_data_from_db;
$fileDownloadCount++;
第二行将值递增1。
其他回答
有一种方法:
$value = json_decode(json_encode($value, JSON_NUMERIC_CHECK|JSON_PRESERVE_ZERO_FRACTION|JSON_UNESCAPED_SLASHES), true);
使用is_*不起作用,因为变量是:string。
使用json_encode()和json_edecode()的组合将其转换为“真”形式。如果它是真字符串,则输出错误。
$num = "Me";
$int = (int)$num;
$float = (float)$num;
var_dump($num, $int, $float);
将输出:string(2)“Me”int(0)float(0)
现在我们正处于一个严格/强类型在PHP中具有更大重要性的时代,我使用json_decode:
$num = json_decode('123');
var_dump($num); // outputs int(123)
$num = json_decode('123.45');
var_dump($num); // outputs float(123.45)
PHP将在限制范围内为您提供
<?php
$str = "3.148";
$num = $str;
printf("%f\n", $num);
?>
要避免出现问题,请尝试intval($var)。一些示例:
<?php
echo intval(42); // 42
echo intval(4.2); // 4
echo intval('42'); // 42
echo intval('+42'); // 42
echo intval('-42'); // -42
echo intval(042); // 34 (octal as starts with zero)
echo intval('042'); // 42
echo intval(1e10); // 1410065408
echo intval('1e10'); // 1
echo intval(0x1A); // 26 (hex as starts with 0x)
echo intval(42000000); // 42000000
echo intval(420000000000000000000); // 0
echo intval('420000000000000000000'); // 2147483647
echo intval(42, 8); // 42
echo intval('42', 8); // 34
echo intval(array()); // 0
echo intval(array('foo', 'bar')); // 1
?>
如果你事先不知道你有一个浮点数还是一个整数,如果字符串可能包含特殊字符(如空格、欧元等),并且如果它可以包含多于1个点或逗号,您可以使用此功能:
// This function strip spaces and other characters from a string and return a number.
// It works for integer and float.
// It expect decimal delimiter to be either a '.' or ','
// Note: everything after an eventual 2nd decimal delimiter will be removed.
function stringToNumber($string) {
// return 0 if the string contains no number at all or is not a string:
if (!is_string($string) || !preg_match('/\d/', $string)) {
return 0;
}
// Replace all ',' with '.':
$workingString = str_replace(',', '.', $string);
// Keep only number and '.':
$workingString = preg_replace("/[^0-9.]+/", "", $workingString);
// Split the integer part and the decimal part,
// (and eventually a third part if there are more
// than 1 decimal delimiter in the string):
$explodedString = explode('.', $workingString, 3);
if ($explodedString[0] === '') {
// No number was present before the first decimal delimiter,
// so we assume it was meant to be a 0:
$explodedString[0] = '0';
}
if (sizeof($explodedString) === 1) {
// No decimal delimiter was present in the string,
// create a string representing an integer:
$workingString = $explodedString[0];
} else {
// A decimal delimiter was present,
// create a string representing a float:
$workingString = $explodedString[0] . '.' . $explodedString[1];
}
// Create a number from this now non-ambiguous string:
$number = $workingString * 1;
return $number;
}