import ftplib
import urllib2
import os
import logging
logger = logging.getLogger('ftpuploader')
hdlr = logging.FileHandler('ftplog.log')
formatter = logging.Formatter('%(asctime)s %(levelname)s %(message)s')
hdlr.setFormatter(formatter)
logger.addHandler(hdlr)
logger.setLevel(logging.INFO)
FTPADDR = "some ftp address"
def upload_to_ftp(con, filepath):
try:
f = open(filepath,'rb') # file to send
con.storbinary('STOR '+ filepath, f) # Send the file
f.close() # Close file and FTP
logger.info('File successfully uploaded to '+ FTPADDR)
except, e:
logger.error('Failed to upload to ftp: '+ str(e))
这似乎不起作用,我遇到语法错误,将所有类型的异常记录到文件中的正确方法是什么
您必须定义要捕获的异常类型。因此,对于一般异常(无论如何都会记录),写Exception,e:而不是Exception。
另一种可能是用这种方式编写整个try/except代码:
try:
with open(filepath,'rb') as f:
con.storbinary('STOR '+ filepath, f)
logger.info('File successfully uploaded to '+ FTPADDR)
except Exception, e: # work on python 2.x
logger.error('Failed to upload to ftp: '+ str(e))
在Python 3.x和Python 2.x的现代版本中,使用Exception作为e,而不是Exception,e:
try:
with open(filepath,'rb') as f:
con.storbinary('STOR '+ filepath, f)
logger.info('File successfully uploaded to '+ FTPADDR)
except Exception as e: # work on python 3.x
logger.error('Failed to upload to ftp: '+ str(e))
还有一种方法可以获得传递给异常类的原始值,而不必更改内容类型。
例如,我在我的一个框架中生成带有错误消息的类型代码。
try:
# TODO: Your exceptional code here
raise Exception((1, "Your code wants the program to exit"))
except Exception as e:
print("Exception Type:", e.args[0][0], "Message:", e.args[0][1])
输出
Exception Type: 1 Message: 'Your code wants the program to exit'