import ftplib
import urllib2
import os
import logging
logger = logging.getLogger('ftpuploader')
hdlr = logging.FileHandler('ftplog.log')
formatter = logging.Formatter('%(asctime)s %(levelname)s %(message)s')
hdlr.setFormatter(formatter)
logger.addHandler(hdlr)
logger.setLevel(logging.INFO)
FTPADDR = "some ftp address"
def upload_to_ftp(con, filepath):
try:
f = open(filepath,'rb') # file to send
con.storbinary('STOR '+ filepath, f) # Send the file
f.close() # Close file and FTP
logger.info('File successfully uploaded to '+ FTPADDR)
except, e:
logger.error('Failed to upload to ftp: '+ str(e))
这似乎不起作用,我遇到语法错误,将所有类型的异常记录到文件中的正确方法是什么
您必须定义要捕获的异常类型。因此,对于一般异常(无论如何都会记录),写Exception,e:而不是Exception。
另一种可能是用这种方式编写整个try/except代码:
try:
with open(filepath,'rb') as f:
con.storbinary('STOR '+ filepath, f)
logger.info('File successfully uploaded to '+ FTPADDR)
except Exception, e: # work on python 2.x
logger.error('Failed to upload to ftp: '+ str(e))
在Python 3.x和Python 2.x的现代版本中,使用Exception作为e,而不是Exception,e:
try:
with open(filepath,'rb') as f:
con.storbinary('STOR '+ filepath, f)
logger.info('File successfully uploaded to '+ FTPADDR)
except Exception as e: # work on python 3.x
logger.error('Failed to upload to ftp: '+ str(e))
使用str(e)或repr(e)表示异常,您将无法获得实际的堆栈跟踪,因此查找异常的位置没有帮助。
在阅读了其他答案和日志记录包文档后,以下两种方法非常适合打印实际堆栈跟踪,以便于调试:
将logger.debug()与参数exc_info一起使用
try:
# my code
except SomeError as e:
logger.debug(e, exc_info=True)
使用logger.exception()
或者我们可以直接使用logger.exception()打印异常。
try:
# my code
except SomeError as e:
logger.exception(e)