let List= [{votes:4},{votes:8},{votes:7}]

let objMax = List.reduce((max, curren) => max.votes > curren.votes ? max : curren);

console.log(objMax)

干净简单的ES6 (Babel)

const maxValueOfY = Math.max(...arrayToSearchIn.map(o => o.y), 0);

如果arrayToSearchIn为空，第二个参数应该确保有一个默认值。

求数组中所有对象的y的最大值:

    Math.max.apply(Math, array.map(function(o) { return o.y; }))

或者在更现代的JavaScript中:

    Math.max(...array.map(o => o.y))

谢谢你在这里找到的答案，我希望它能对别人有用。 这个typescript函数可以被调用来搜索数组对象字段中可能存在的最大值:

function getHighestField(objArray: any[], fieldName: string) {
  return Number(
    Math.max.apply(
      Math,
      objArray?.map(o => o[fieldName] || 0),
    ) || 0,
  );
}

以这些值为例:

const scoreBoard = [
  { name: 'player1', score: 4 },
  { name: 'player2', score: 9 },
  { name: 'player3', score: 7 }
]

你可以这样调用这个函数:

const myHighestVariable = `This is the highest: ${getHighestField(scoreBoard, "score")}`;

结果会是这样的:

console.log(myHighestVariable);

这是最高的:9

首先，你应该解析JSON字符串，这样你就可以很容易地访问它的成员:

var arr = $.parseJSON(str);

使用map方法提取值:

arr = $.map(arr, function(o){ return o.y; });

然后你可以在max方法中使用数组:

var highest = Math.max.apply(this,arr);

或者作为一行语句:

var highest = Math.max.apply(this,$.map($.parseJSON(str), function(o){ return o.y; }));

// Here is very simple way to go:

// Your DataSet.

let numberArray = [
  {
    "x": "8/11/2009",
    "y": 0.026572007
  },
  {
    "x": "8/12/2009",
    "y": 0.025057454
  },
  {
    "x": "8/13/2009",
    "y": 0.024530916
  },
  {
    "x": "8/14/2009",
    "y": 0.031004457
  }
]

// 1. First create Array, containing all the value of Y
let result = numberArray.map((y) => y)
console.log(result) // >> [0.026572007,0.025057454,0.024530916,0.031004457]

// 2.
let maxValue = Math.max.apply(null, result)
console.log(maxValue) // >> 0.031004457