ES6解决方案

Math.max(…array.map(函数(o){返回o.y;}))

详情见https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/max

// Here is very simple way to go:

// Your DataSet.

let numberArray = [
  {
    "x": "8/11/2009",
    "y": 0.026572007
  },
  {
    "x": "8/12/2009",
    "y": 0.025057454
  },
  {
    "x": "8/13/2009",
    "y": 0.024530916
  },
  {
    "x": "8/14/2009",
    "y": 0.031004457
  }
]

// 1. First create Array, containing all the value of Y
let result = numberArray.map((y) => y)
console.log(result) // >> [0.026572007,0.025057454,0.024530916,0.031004457]

// 2.
let maxValue = Math.max.apply(null, result)
console.log(maxValue) // >> 0.031004457

以下是ES6的最短解决方案(One Liner):

Math.max(...values.map(o => o.y));

在对象数组中找到属性“Y”值最大的对象

一种方法是使用Array reduce..

const max = data.reduce(function(prev, current) {
    return (prev.y > current.y) ? prev : current
}) //returns object

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce http://caniuse.com/#search=reduce (IE9及以上版本)

如果你不需要支持IE(只支持Edge)，或者可以使用预编译器，比如Babel，你可以使用更简洁的语法。

const max = data.reduce((prev, current) => (prev.y > current.y) ? prev : current)

它返回对象简化的@andy polhill answare

var data = ( ｛ y: 90 }， ｛ y: 9 }， ｛ y: 8 ｝ ］ Const Max = data。Reduce ((prev, current)=> ((prev, current))Y >电流。Y) ?当前)，0)//返回对象 console.log (max)

求数组中所有对象的y的最大值:

    Math.max.apply(Math, array.map(function(o) { return o.y; }))

或者在更现代的JavaScript中:

    Math.max(...array.map(o => o.y))