对于像我这样的懒人:

Kip的答案(从上面)在coffeescript中，使用“enum”，并对同一对象进行操作:

Date.UNIT =
  YEAR: 0
  QUARTER: 1
  MONTH: 2
  WEEK: 3
  DAY: 4
  HOUR: 5
  MINUTE: 6
  SECOND: 7
Date::add = (unit, quantity) ->
  switch unit
    when Date.UNIT.YEAR then @setFullYear(@getFullYear() + quantity)
    when Date.UNIT.QUARTER then @setMonth(@getMonth() + (3 * quantity))
    when Date.UNIT.MONTH then @setMonth(@getMonth() + quantity)
    when Date.UNIT.WEEK then @setDate(@getDate() + (7 * quantity))
    when Date.UNIT.DAY then @setDate(@getDate() + quantity)
    when Date.UNIT.HOUR then @setTime(@getTime() + (3600000 * quantity))
    when Date.UNIT.MINUTE then @setTime(@getTime() + (60000 * quantity))
    when Date.UNIT.SECOND then @setTime(@getTime() + (1000 * quantity))
    else throw new Error "Unrecognized unit provided"
  @ # for chaining

您应该获取当前日期的值以获得日期(ms)，并向其添加(30 * 60 *1000)。现在你有(当前日期+ 30分钟)ms

console.log('with ms'， Date.now() + (30 * 60 * 1000)) console.log('new Date'， new Date(Date.now() + (30 * 60 * 1000)))

我总是创建7个函数，在JS中使用date: addSeconds, addMinutes, addHours, addDays, addWeeks, addMonths, addYears。

你可以在这里看到一个例子:http://jsfiddle.net/tiagoajacobi/YHA8x/

使用方法:

var now = new Date();
console.log(now.addMinutes(30));
console.log(now.addWeeks(3));

这些是函数:

Date.prototype.addSeconds = function(seconds) {
  this.setSeconds(this.getSeconds() + seconds);
  return this;
};

Date.prototype.addMinutes = function(minutes) {
  this.setMinutes(this.getMinutes() + minutes);
  return this;
};

Date.prototype.addHours = function(hours) {
  this.setHours(this.getHours() + hours);
  return this;
};

Date.prototype.addDays = function(days) {
  this.setDate(this.getDate() + days);
  return this;
};

Date.prototype.addWeeks = function(weeks) {
  this.addDays(weeks*7);
  return this;
};

Date.prototype.addMonths = function (months) {
  var dt = this.getDate();
  this.setMonth(this.getMonth() + months);
  var currDt = this.getDate();
  if (dt !== currDt) {  
    this.addDays(-currDt);
  }
  return this;
};

Date.prototype.addYears = function(years) {
  var dt = this.getDate();
  this.setFullYear(this.getFullYear() + years);
  var currDt = this.getDate();
  if (dt !== currDt) {  
    this.addDays(-currDt);
  }
  return this;
};

var add_minutes =  function (dt, minutes) {
return new Date(dt.getTime() + minutes*60000);
}
 console.log(add_minutes(new Date(2014,10,2), 30).toString());

下面是我的一句话:

console.log('time: '， new Date(new Date().valueOf() + 60000))

你可以这样做:

let 30tyminutes = 30 * 60 * 1000;//将30分钟转换为毫秒 let date1 = new Date(); let date2 = new Date(date1.getTime() + 30tyminutes); console.log (date1); console.log (date2);