我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?


当前回答

对于像我这样的懒人:

Kip的答案(从上面)在coffeescript中,使用“enum”,并对同一对象进行操作:

Date.UNIT =
  YEAR: 0
  QUARTER: 1
  MONTH: 2
  WEEK: 3
  DAY: 4
  HOUR: 5
  MINUTE: 6
  SECOND: 7
Date::add = (unit, quantity) ->
  switch unit
    when Date.UNIT.YEAR then @setFullYear(@getFullYear() + quantity)
    when Date.UNIT.QUARTER then @setMonth(@getMonth() + (3 * quantity))
    when Date.UNIT.MONTH then @setMonth(@getMonth() + quantity)
    when Date.UNIT.WEEK then @setDate(@getDate() + (7 * quantity))
    when Date.UNIT.DAY then @setDate(@getDate() + quantity)
    when Date.UNIT.HOUR then @setTime(@getTime() + (3600000 * quantity))
    when Date.UNIT.MINUTE then @setTime(@getTime() + (60000 * quantity))
    when Date.UNIT.SECOND then @setTime(@getTime() + (1000 * quantity))
    else throw new Error "Unrecognized unit provided"
  @ # for chaining

其他回答

这就是我所做的,似乎很有效:

Date.prototype.addMinutes = function(minutes) {
    var copiedDate = new Date(this.getTime());
    return new Date(copiedDate.getTime() + minutes * 60000);
}

然后你可以这样调用它:

var now = new Date();
console.log(now.addMinutes(50));

事情就是这么简单;

let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));
var add_minutes =  function (dt, minutes) {
return new Date(dt.getTime() + minutes*60000);
}
 console.log(add_minutes(new Date(2014,10,2), 30).toString());
let d = new Date();
d.setMinutes(d.getMinutes() + 30);

// console.log(d)

下面是我的一句话:

console.log('time: ', new Date(new Date().valueOf() + 60000))