我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?
当前回答
对于像我这样的懒人:
Kip的答案(从上面)在coffeescript中,使用“enum”,并对同一对象进行操作:
Date.UNIT =
YEAR: 0
QUARTER: 1
MONTH: 2
WEEK: 3
DAY: 4
HOUR: 5
MINUTE: 6
SECOND: 7
Date::add = (unit, quantity) ->
switch unit
when Date.UNIT.YEAR then @setFullYear(@getFullYear() + quantity)
when Date.UNIT.QUARTER then @setMonth(@getMonth() + (3 * quantity))
when Date.UNIT.MONTH then @setMonth(@getMonth() + quantity)
when Date.UNIT.WEEK then @setDate(@getDate() + (7 * quantity))
when Date.UNIT.DAY then @setDate(@getDate() + quantity)
when Date.UNIT.HOUR then @setTime(@getTime() + (3600000 * quantity))
when Date.UNIT.MINUTE then @setTime(@getTime() + (60000 * quantity))
when Date.UNIT.SECOND then @setTime(@getTime() + (1000 * quantity))
else throw new Error "Unrecognized unit provided"
@ # for chaining
其他回答
这就是我所做的,似乎很有效:
Date.prototype.addMinutes = function(minutes) {
var copiedDate = new Date(this.getTime());
return new Date(copiedDate.getTime() + minutes * 60000);
}
然后你可以这样调用它:
var now = new Date();
console.log(now.addMinutes(50));
事情就是这么简单;
let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));
var add_minutes = function (dt, minutes) {
return new Date(dt.getTime() + minutes*60000);
}
console.log(add_minutes(new Date(2014,10,2), 30).toString());
let d = new Date();
d.setMinutes(d.getMinutes() + 30);
// console.log(d)
下面是我的一句话:
console.log('time: ', new Date(new Date().valueOf() + 60000))