在SQL Server上获得特定数据库中所有表的名称的最佳方法是什么?
当前回答
Any of the T-SQL code below will work in SQL Server 2019:
-- here, you need to prefix the database name in INFORMATION_SCHEMA.TABLES
SELECT TABLE_NAME FROM [MSSQL-TEST].INFORMATION_SCHEMA.TABLES;
-- The next 2 ways will require you to point
-- to the specific database you want to list the tables
USE [MSSQL-TEST];
-- (1) Using sys.tables
SELECT * FROM sys.tables;
-- (2) Using sysobjects
SELECT * FROM sysobjects
WHERE type='U';
Here’s a working example using [Skyvia] using sys.tables.
[Skyvia] should be the link to https://skyvia.com/connectors/sql-server
[1]: https://i.stack.imgur.com/o3qo9.png
Your SQL GUI tool should also have a way to list down all the tables in a database like the one above.
So, whatever suits your need and taste, there’s a code or GUI tool for that.
其他回答
使用SELECT * FROM INFORMATION_SCHEMA。COLUMNS还显示所有表和相关列。
SELECT sobjects.name
FROM sysobjects sobjects
WHERE sobjects.xtype = 'U'
INFORMATION_SCHEMA的缺点。它还包括系统表,如dtproperties和MSpeer_…表,没有办法把它们和你自己的表区分开来。
我建议使用sys。对象(已弃用的sysobjects视图的新版本),它支持排除系统表:
select *
from sys.objects
where type = 'U' -- User tables
and is_ms_shipped = 0 -- Exclude system tables
USE YourDBName
GO
SELECT *
FROM sys.Tables
GO
OR
USE YourDBName
GO
SELECT * FROM INFORMATION_SCHEMA.TABLES
GO
你可以用sys。对象来获取所有数据库对象。
GO
select * from sys.objects where type_desc='USER_TABLE' order by name
GO
OR
-- For all tables
select * from INFORMATION_SCHEMA.TABLES
GO
--- For user defined tables
select * from INFORMATION_SCHEMA.TABLES where TABLE_TYPE='BASE TABLE'
GO
--- For Views
select * from INFORMATION_SCHEMA.TABLES where TABLE_TYPE='VIEW'
GO