我在Android中玩碎片。

我知道我可以通过使用以下代码更改一个片段:

FragmentManager fragMgr = getSupportFragmentManager();
FragmentTransaction fragTrans = fragMgr.beginTransaction();

MyFragment myFragment = new MyFragment(); //my custom fragment

fragTrans.replace(android.R.id.content, myFragment);
fragTrans.addToBackStack(null);
fragTrans.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
fragTrans.commit();

我的问题是,在Java文件中,如何获得当前显示的片段实例?


当前回答

也许最简单的方法是:

public MyFragment getVisibleFragment(){
    FragmentManager fragmentManager = MainActivity.this.getSupportFragmentManager();
    List<Fragment> fragments = fragmentManager.getFragments();
    for(Fragment fragment : fragments){
        if(fragment != null && fragment.getUserVisibleHint())
            return (MyFragment)fragment;
    }
    return null;
}

这对我很有效

其他回答

反应式方式:

Observable.from(getSupportFragmentManager().getFragments())
    .filter(fragment -> fragment.isVisible())
    .subscribe(fragment1 -> {
        // Do something with it
    }, throwable1 -> {
        // 
    });

这是我的工作。我希望这能帮助到某人。

FragmentManager fragmentManager = this.getSupportFragmentManager();  
        String tag = fragmentManager
                    .getBackStackEntryAt(
                    fragmentManager
                    .getBackStackEntryCount() - 1)
                    .getName();
              Log.d("This is your Top Fragment name: ", ""+tag);

你好,我知道这是一个非常老的问题,但我想分享我自己的解决方案。

为了获得用户浏览的片段列表,我创建了一个helper类:

public class MyHelperClass{

    private static ArrayList<Fragment> listFragment = new ArrayList<>();

    public static void addFragment(Fragment f){
        if(!existFragment(f)) {
            listFragment.add(f);
        }
    }
    public static void removeFragment(){
        if(listFragment.size()>0)
            listFragment.remove(listFragment.size()-1);
    }
    public static Fragment getCurrentFragment(){
        return listFragment.get(listFragment.size()-1);
    }
    public static int sizeFragments(){
        return listFragment.size();
    }
    private static Boolean existFragment(Fragment f){
        Boolean ret = false;
        for(Fragment fragment : listFragment){
            if (fragment.getClass() == f.getClass()){
                ret = true;
            }
        }
        return ret;
    }

进入主活动,我重写onAttachFragment方法

@Override
public void onAttachFragment(Fragment f) {
    super.onAttachFragment(f);

    MyHelperClass.addFragment(f);
}

并且,我重写onBackPressed方法:

@Override
public void onBackPressed() {
        General.removeFragment();
        if(General.sizeFragments()>0){
            Fragment fragment = null;
            Class fragmentClass = General.getCurrentFragment().getClass();

            try {
                fragment = (Fragment) fragmentClass.newInstance();
                fragment.setArguments(General.getCurrentFragment().getArguments());
            } catch (Exception e) {
                e.printStackTrace();
            }

            fragmentManager.beginTransaction().replace(R.id.flContent, fragment).commit();
        }else{
            super.onBackPressed();
        }
}

所以通过这种方式,你可以在任何时候通过MyHelperClass.getCurrentFragment()获得活动片段

我希望这对任何人都有帮助

问候

有点奇怪,但我看了FragmentManager$FragmentManagerImpl和以下工作为我:

public static Fragment getActiveFragment(Activity activity, int index)
{
    Bundle bundle = new Bundle();
    String key = "i";
    bundle.putInt(key,index);
    Fragment fragment=null;
    try
    {
        fragment = activity.getFragmentManager().getFragment(bundle, key);
    } catch(Exception e){}
    return fragment;
}

要获得第一个活动片段,请使用0作为索引

1)

ft.replace(R.id.content_frame, fragment, **tag**).commit();

2)

FragmentManager fragmentManager = getSupportFragmentManager();
Fragment currentFragment = fragmentManager.findFragmentById(R.id.content_frame);

3)

if (currentFragment.getTag().equals(**"Fragment_Main"**))
{
 //Do something
}
else
if (currentFragment.getTag().equals(**"Fragment_DM"**))
{
//Do something
}