我可以运行这个查询来获得MySQL数据库中所有表的大小:
show table status from myDatabaseName;
我希望有人能帮助我理解结果。我在找尺寸最大的桌子。
我应该看哪一列?
我可以运行这个查询来获得MySQL数据库中所有表的大小:
show table status from myDatabaseName;
我希望有人能帮助我理解结果。我在找尺寸最大的桌子。
我应该看哪一列?
当前回答
select x.dbname as db_name, x.table_name as table_name, x.bytesize as the_size from
(select
table_schema as dbname,
sum(index_length+data_length) as bytesize,
table_name
from
information_schema.tables
group by table_schema
) x
where
x.bytesize > 999999
order by x.bytesize desc;
其他回答
另一种显示所占用的行数和空间并按其排序的方法。
SELECT
table_schema as `Database`,
table_name AS `Table`,
table_rows AS "Quant of Rows",
round(((data_length + index_length) / 1024 / 1024/ 1024), 2) `Size in GB`
FROM information_schema.TABLES
WHERE table_schema = 'yourDatabaseName'
ORDER BY (data_length + index_length) DESC;
在这个查询中唯一需要替换的字符串是“yourDatabaseName”。
如果您正在使用phpmyadmin,那么只需转到表结构
e.g.
Space usage
Data 1.5 MiB
Index 0 B
Total 1.5 Mi
如果您想查询使用当前选定的数据库。简单地复制粘贴这个查询。(无需修改)
SELECT table_name ,
round(((data_length + index_length) / 1024 / 1024), 2) as SIZE_MB
FROM information_schema.TABLES
WHERE table_schema = DATABASE() ORDER BY SIZE_MB DESC;
SELECT TABLE_NAME AS table_name,
table_rows AS QuantofRows,
ROUND((data_length + index_length) /1024, 2 ) AS total_size_kb
FROM information_schema.TABLES
WHERE information_schema.TABLES.table_schema = 'db'
ORDER BY (data_length + index_length) DESC;
以上2个都是在mysql上测试的
尝试以下shell命令(将DB_NAME替换为您的数据库名称):
mysql -uroot <<<"SELECT table_name AS 'Tables', round((data_length + index_length) / 1024 / 1024), 2)Size in MB FROM information_schematable WHERE table_schema = \"DB_NAME\" ORDER BY (data_length + index_length) DESC;"|头
对于Drupal/drush解决方案,检查下面的示例脚本,它将显示正在使用的最大表:
#!/bin/sh
DB_NAME=$(drush status --fields=db-name --field-labels=0 | tr -d '\r\n ')
drush sqlq "SELECT table_name AS 'Tables', round(((data_length + index_length) / 1024 / 1024), 2) 'Size in MB' FROM information_schema.TABLES WHERE table_schema = \"${DB_NAME}\" ORDER BY (data_length + index_length) DESC;" | head -n20