我可以运行这个查询来获得MySQL数据库中所有表的大小:
show table status from myDatabaseName;
我希望有人能帮助我理解结果。我在找尺寸最大的桌子。
我应该看哪一列?
我可以运行这个查询来获得MySQL数据库中所有表的大小:
show table status from myDatabaseName;
我希望有人能帮助我理解结果。我在找尺寸最大的桌子。
我应该看哪一列?
当前回答
SELECT TABLE_NAME AS table_name,
table_rows AS QuantofRows,
ROUND((data_length + index_length) /1024, 2 ) AS total_size_kb
FROM information_schema.TABLES
WHERE information_schema.TABLES.table_schema = 'db'
ORDER BY (data_length + index_length) DESC;
以上2个都是在mysql上测试的
其他回答
如果您正在使用phpmyadmin,那么只需转到表结构
e.g.
Space usage
Data 1.5 MiB
Index 0 B
Total 1.5 Mi
我发现现有的答案实际上并没有给出磁盘上表的大小,这更有帮助。 与基于data_length的表大小相比,此查询提供了更准确的磁盘估计 和索引。我不得不在AWS RDS实例中使用这种方法,因为您无法物理地检查磁盘和检查文件大小。
select NAME as TABLENAME,FILE_SIZE/(1024*1024*1024) as ACTUAL_FILE_SIZE_GB
, round(((data_length + index_length) / 1024 / 1024/1024), 2) as REPORTED_TABLE_SIZE_GB
from INFORMATION_SCHEMA.INNODB_SYS_TABLESPACES s
join INFORMATION_SCHEMA.TABLES t
on NAME = Concat(table_schema,'/',table_name)
order by FILE_SIZE desc
最后计算数据库的总大小:
(SELECT
table_name AS `Table`,
round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB`
FROM information_schema.TABLES
WHERE table_schema = "$DB_NAME"
)
UNION ALL
(SELECT
'TOTAL:',
SUM(round(((data_length + index_length) / 1024 / 1024), 2) )
FROM information_schema.TABLES
WHERE table_schema = "$DB_NAME"
)
select x.dbname as db_name, x.table_name as table_name, x.bytesize as the_size from
(select
table_schema as dbname,
sum(index_length+data_length) as bytesize,
table_name
from
information_schema.tables
group by table_schema
) x
where
x.bytesize > 999999
order by x.bytesize desc;
改编自ChapMic的回答,以满足我的特殊需要。
只指定数据库名称,然后按降序对所有表进行排序——在所选数据库中从最大到最小的表。只需要替换1个变量=数据库名。
SELECT
table_name AS `Table`,
round(((data_length + index_length) / 1024 / 1024), 2) AS `size`
FROM information_schema.TABLES
WHERE table_schema = "YOUR_DATABASE_NAME_HERE"
ORDER BY size DESC;