我可以运行这个查询来获得MySQL数据库中所有表的大小:
show table status from myDatabaseName;
我希望有人能帮助我理解结果。我在找尺寸最大的桌子。
我应该看哪一列?
我可以运行这个查询来获得MySQL数据库中所有表的大小:
show table status from myDatabaseName;
我希望有人能帮助我理解结果。我在找尺寸最大的桌子。
我应该看哪一列?
当前回答
如果您想查询使用当前选定的数据库。简单地复制粘贴这个查询。(无需修改)
SELECT table_name ,
round(((data_length + index_length) / 1024 / 1024), 2) as SIZE_MB
FROM information_schema.TABLES
WHERE table_schema = DATABASE() ORDER BY SIZE_MB DESC;
其他回答
Size of all tables: Suppose your database or TABLE_SCHEMA name is "news_alert". Then this query will show the size of all tables in the database. SELECT TABLE_NAME AS `Table`, ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024),2) AS `Size (MB)` FROM information_schema.TABLES WHERE TABLE_SCHEMA = "news_alert" ORDER BY (DATA_LENGTH + INDEX_LENGTH) DESC; Output: +---------+-----------+ | Table | Size (MB) | +---------+-----------+ | news | 0.08 | | keyword | 0.02 | +---------+-----------+ 2 rows in set (0.00 sec) For the specific table: Suppose your TABLE_NAME is "news". Then SQL query will be- SELECT TABLE_NAME AS `Table`, ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024),2) AS `Size (MB)` FROM information_schema.TABLES WHERE TABLE_SCHEMA = "news_alert" AND TABLE_NAME = "news" ORDER BY (DATA_LENGTH + INDEX_LENGTH) DESC; Output: +-------+-----------+ | Table | Size (MB) | +-------+-----------+ | news | 0.08 | +-------+-----------+ 1 row in set (0.00 sec)
你可以使用这个查询来显示表的大小(尽管你需要先替换变量):
SELECT
table_name AS `Table`,
round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB`
FROM information_schema.TABLES
WHERE table_schema = "$DB_NAME"
AND table_name = "$TABLE_NAME";
或者这个查询列出每个数据库中每个表的大小,最大的先:
SELECT
table_schema as `Database`,
table_name AS `Table`,
round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB`
FROM information_schema.TABLES
ORDER BY (data_length + index_length) DESC;
我使用这个shell脚本来跟踪表大小(以字节和行数为单位)
#!/bin/sh
export MYSQL_PWD=XXXXXXXX
TABLES="table1 table2 table3"
for TABLE in $TABLES;
do
FILEPATH=/var/lib/mysql/DBNAME/$TABLE.ibd
TABLESIZE=`wc -c $FILEPATH | awk '{print $1}'`
#Size in Bytes
mysql -D scarprd_self -e "INSERT INTO tables_sizes (table_name,table_size,measurement_type) VALUES ('$TABLE', '$TABLESIZE', 'BYTES');"
#Size in rows
ROWSCOUNT=$(mysql -D scarprd_self -e "SELECT COUNT(*) AS ROWSCOUNT FROM $TABLE;")
ROWSCOUNT=${ROWSCOUNT//ROWSCOUNT/}
mysql -D scarprd_self -e "INSERT INTO tables_sizes (table_name,table_size,measurement_type) VALUES ('$TABLE', '$ROWSCOUNT', 'ROWSCOUNT');"
mysql -D scarprd_self -e "DELETE FROM tables_sizes WHERE measurement_datetime < TIMESTAMP(DATE_SUB(NOW(), INTERVAL 365 DAY));"
done
它假设有这个MySQL表
CREATE TABLE `tables_sizes` (
`table_name` VARCHAR(128) NOT NULL,
`table_size` VARCHAR(25) NOT NULL,
`measurement_type` VARCHAR(10) NOT NULL CHECK (measurement_type IN ('BYTES','ROWSCOUNT')),
`measurement_datetime` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP()
) ENGINE=INNODB DEFAULT CHARSET=utf8
这只是一个供以后参考的说明。所有答案都依赖于I_S.TABLES。例如,如果你在表中有blob字段,它不会告诉你正确的大小。LOB页存储在外部页中,因此不计入聚集索引。 事实上有一个注释:
对于NDB表,该语句的输出显示适当的值 AVG_ROW_LENGTH和DATA_LENGTH列,例外 没有考虑到BLOB列。
我发现InnoDB也是如此。
我已经创建了社区Bug相同。
SELECT TABLE_NAME AS "Table Name",
table_rows AS "Quant of Rows", ROUND( (
data_length + index_length
) /1024, 2 ) AS "Total Size Kb"
FROM information_schema.TABLES
WHERE information_schema.TABLES.table_schema = 'YOUR SCHEMA NAME/DATABASE NAME HERE'
LIMIT 0 , 30
您可以从“information_schema”-> SCHEMATA表->“SCHEMA_NAME”列中获取模式名称
额外的 你可以得到mysql数据库的大小如下。
SELECT table_schema "DB Name",
Round(Sum(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB"
FROM information_schema.tables
GROUP BY table_schema
ORDER BY `DB Size in MB` DESC;
结果
DB Name | DB Size in MB
mydatabase_wrdp 39.1
information_schema 0.0
你可以在这里得到更多的细节。