试试这个，它是有效的:

mButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {

                mSlotLayout.setEnabled(false);

        //      do your work here

                Timer buttonTimer = new Timer();
                buttonTimer.schedule(new TimerTask() {

                    @Override
                    public void run() {

                        runOnUiThread(new Runnable() {

                            @Override
                            public void run() {
                                mButton.setEnabled(true);
                            }
                        });
                    }
                }, 500); // delay button enable for 0.5 sec
    }
});

setEnabled(false)非常适合我。

我写{setEnabled(true);}，并在第一次点击按钮时将其设为false。

我的解决方案(Kotlin):

class OnDebouncedClickListener(private val delayInMilliSeconds: Long, val action: () -> Unit) : View.OnClickListener {
    var enable = true

    override fun onClick(view: View?) {
        if (enable) {
            enable = false
            view?.postDelayed(delayInMilliSeconds) { enable = true }
            action()
        }
    }
}

fun View.setOnDebouncedClickListener(delayInMilliSeconds: Long = 500, action: () -> Unit) {
    val onDebouncedClickListener = OnDebouncedClickListener(delayInMilliSeconds, action)
    setOnClickListener(onDebouncedClickListener)
}

使用:

button.apply {       
            setOnDebouncedClickListener {
                //your action on click
            }
        }

更可取的解决方案是，

onclick(){
  btn.setEnabled(false);
  btn.setClickable(false);
  //yourwork
  myWork();
}

myWork(){
 //your tasks.
 btn.setEnabled(true);
 btn.setClickable(true);
}

由于一个环节很容易被忽略，我不得不一遍又一遍地重复这个环节

这是我的解决方案:

if (waitDouble) {
    waitDouble = false;
    Thread thread = new Thread() {
        @Override
        public void run() {
            try {
                sleep(300);
                if (waitDouble == false) {
                    waitDouble = true;
                    singleClick();  //singleClick
                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    };
    thread.start();
} else {//DoubleClick
    DoubleClick();
    waitDouble = true;
}

或者另一种解决方案:

public class NoDoubleClickUtils {
    private static long lastClickTime;
    private final static int SPACE_TIME = 500;

    public static void initLastClickTime() {
        lastClickTime = 0;
    }

    public synchronized static boolean isDoubleClick() {
        long currentTime = System.currentTimeMillis();
        boolean isClick2;
        if (currentTime - lastClickTime > SPACE_TIME) {
            isClick2 = false;
        } else {
            isClick2 = true;
        }
        lastClickTime = currentTime;
        return isClick2;
    }
}

加上Jim的回答，代码可以变得更简洁:

fun View.setOnSingleClick(onClick: () -> Unit) {
    var lastClickTime = 0L
    setOnClickListener {
        if (currentTimeMillis() > lastClickTime + 750) onClick()
        lastClickTime = currentTimeMillis()
    } 
}

用法:

aView.setOnSingleClick {  }