在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
更可取的解决方案是,
onclick(){
btn.setEnabled(false);
btn.setClickable(false);
//yourwork
myWork();
}
myWork(){
//your tasks.
btn.setEnabled(true);
btn.setClickable(true);
}
由于一个环节很容易被忽略,我不得不一遍又一遍地重复这个环节
其他回答
我的解决方案是
package com.shuai.view;
import android.os.SystemClock;
import android.view.View;
/**
* 处理快速在某个控件上双击2次(或多次)会导致onClick被触发2次(或多次)的问题
* 通过判断2次click事件的时间间隔进行过滤
*
* 子类通过实现{@link #onSingleClick}响应click事件
*/
public abstract class OnSingleClickListener implements View.OnClickListener {
/**
* 最短click事件的时间间隔
*/
private static final long MIN_CLICK_INTERVAL=600;
/**
* 上次click的时间
*/
private long mLastClickTime;
/**
* click响应函数
* @param v The view that was clicked.
*/
public abstract void onSingleClick(View v);
@Override
public final void onClick(View v) {
long currentClickTime=SystemClock.uptimeMillis();
long elapsedTime=currentClickTime-mLastClickTime;
//有可能2次连击,也有可能3连击,保证mLastClickTime记录的总是上次click的时间
mLastClickTime=currentClickTime;
if(elapsedTime<=MIN_CLICK_INTERVAL)
return;
onSingleClick(v);
}
}
用法类似于OnClickListener,但重写onSingleClick()代替:
mTextView.setOnClickListener(new OnSingleClickListener() {
@Override
public void onSingleClick(View v) {
if (DEBUG)
Log.i("TAG", "onclick!");
}
};
你可以用Kotlin扩展函数和RxBinding来实现它
fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit): Disposable =
RxView.clicks(this)
.debounce(debounceTime, TimeUnit.MILLISECONDS)
.observeOn(AndroidSchedulers.mainThread())
.subscribe { action() }
or
fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit) {
this.setOnClickListener(object : View.OnClickListener {
private var lastClickTime: Long = 0
override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - lastClickTime < debounceTime) return
else action()
lastClickTime = SystemClock.elapsedRealtime()
}
})
}
然后就是:
View.clickWithDebounce{ Your code }
我希望这能帮助你,把代码放在你的事件处理程序。
// --------------------------------------------------------------------------------
boolean hasTag = null != which.getTag( R.id.preventing_double_click_tag );
if ( hasTag ) {
// Do not handle again...
return;
} else {
which.setTag( R.id.action, Boolean.TRUE );
which.postDelayed( new Runnable() {
@Override
public void run() {
which.setTag( R.id.action, null );
Log.d( "onActin", " The preventing double click tag was removed." );
}
}, 2000 );
}
The Best and simple solution i found is
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;
/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}
我的解决方案是尝试使用一个布尔变量:
public class Blocker {
private static final int DEFAULT_BLOCK_TIME = 1000;
private boolean mIsBlockClick;
/**
* Block any event occurs in 1000 millisecond to prevent spam action
* @return false if not in block state, otherwise return true.
*/
public boolean block(int blockInMillis) {
if (!mIsBlockClick) {
mIsBlockClick = true;
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
mIsBlockClick = false;
}
}, blockInMillis);
return false;
}
return true;
}
public boolean block() {
return block(DEFAULT_BLOCK_TIME);
}
}
并使用如下:
view.setOnClickListener(new View.OnClickListener() {
private Blocker mBlocker = new Blocker();
@Override
public void onClick(View v) {
if (!mBlocker.block(block-Time-In-Millis)) {
// do your action
}
}
});
更新:Kotlin解决方案,使用视图扩展
fun View.safeClick(listener: View.OnClickListener, blockInMillis: Long = 500) {
var lastClickTime: Long = 0
this.setOnClickListener {
if (SystemClock.elapsedRealtime() - lastClickTime < blockInMillis) return@setOnClickListener
lastClickTime = SystemClock.elapsedRealtime()
listener.onClick(this)
}
}
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