加上Jim的回答，代码可以变得更简洁:

fun View.setOnSingleClick(onClick: () -> Unit) {
    var lastClickTime = 0L
    setOnClickListener {
        if (currentTimeMillis() > lastClickTime + 750) onClick()
        lastClickTime = currentTimeMillis()
    } 
}

用法:

aView.setOnSingleClick {  }

Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).

在点击的时候保存最后一次点击的时间可以避免这个问题。

i.e.

private long mLastClickTime = 0;

...

// inside onCreate or so:

findViewById(R.id.button).setOnClickListener(new OnClickListener() {
    @Override
    public void onClick(View v) {
        // mis-clicking prevention, using threshold of 1000 ms
        if (SystemClock.elapsedRealtime() - mLastClickTime < 1000){
            return;
        }
        mLastClickTime = SystemClock.elapsedRealtime();

        // do your magic here
    }
}

试试这个，它是有效的:

mButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {

                mSlotLayout.setEnabled(false);

        //      do your work here

                Timer buttonTimer = new Timer();
                buttonTimer.schedule(new TimerTask() {

                    @Override
                    public void run() {

                        runOnUiThread(new Runnable() {

                            @Override
                            public void run() {
                                mButton.setEnabled(true);
                            }
                        });
                    }
                }, 500); // delay button enable for 0.5 sec
    }
});

这个问题的实际解决方案是使用setEnabled(false)，灰色按钮，和setClickable(false)，使它第二次点击不能接收，我已经测试过了，它似乎是非常有效的。

在我的情况下，我使用按钮视图，它的点击速度太快了。只需禁用点击，并在几秒钟后再次启用它…

基本上我做了一个包装类，包装你的Views onClickListener。如果您愿意，还可以设置自定义延迟。

public class OnClickRateLimitedDecoratedListener implements View.OnClickListener {

    private final static int CLICK_DELAY_DEFAULT = 300;
    private View.OnClickListener onClickListener;
    private int mClickDelay;


        public OnClickRateLimitedDecoratedListener(View.OnClickListener onClickListener) {
            this(onClickListener, CLICK_DELAY_DEFAULT);
        }

        //customize your own delay
        public OnClickRateLimitedDecoratedListener(View.OnClickListener onClickListener, int delay) {
            this.onClickListener = onClickListener;
            mClickDelay = delay;
        }

        @Override
        public void onClick(final View v) {
            v.setClickable(false);
            onClickListener.onClick(v);

            v.postDelayed(new Runnable() {
                @Override
                public void run() {
                    v.setClickable(true);
                }
            }, mClickDelay);
        }
    }

简单地调用它:

mMyButton.setOnClickListener(new OnClickRateLimitedDecoratedListener(new View.OnClickListener() {
             @Override
             public void onClick(View v) {
                 doSomething();
             }
         }));

或者提供你自己的延迟:

 mMyButton.setOnClickListener(new OnClickRateLimitedDecoratedListener(new View.OnClickListener() {
                     @Override
                     public void onClick(View v) {
                         doSomething();
                     }
                 },1000));

更新:以上方式有点过时，现在RxJava是如此流行。正如其他人所提到的，在android中我们可以使用油门来减慢点击。这里有一个例子:

 RxView.clicks(myButton)
                    .throttleFirst(2000, TimeUnit.MILLISECONDS, AndroidSchedulers.mainThread())
                    .subscribe {
                        Log.d("i got delayed clicked")
                    }
        }

实现'com. jake沃顿。rxbinding:2.0.0'