我在MySQL数据库中有数据。我向用户发送一个URL,以获取他们的数据作为CSV文件。

我有链接的电子邮件,MySQL查询等覆盖。

当他们点击链接时,如何弹出从MySQL下载带有记录的CVS的窗口?

我已经有了所有能拿到唱片的资料。我只是不明白如何让PHP创建CSV文件,并让他们下载一个扩展名为. CSV的文件。


当前回答

而不是:

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error()); 

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    $result.="{$row['email']},";
    $result.="\n";
    echo $result;
}

Use:

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error()); 

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    echo implode(",", $row)."\n";
}

其他回答

编写自己的CSV代码可能是浪费你的时间,只是使用一个包,如league/ CSV -它为你处理所有困难的事情,文档是很好的,它是非常稳定/可靠的:

http://csv.thephpleague.com/

你需要使用作曲家。如果你不知道什么是作曲家,我强烈建议你去看看:https://getcomposer.org/

要让它以CSV格式发送,并给出文件名,请使用header():

http://us2.php.net/header

header('Content-type: text/csv');
header('Content-disposition: attachment; filename="myfile.csv"');

至于创建CSV本身,您只需要遍历结果集,格式化输出并发送它,就像处理任何其他内容一样。

而不是:

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error()); 

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    $result.="{$row['email']},";
    $result.="\n";
    echo $result;
}

Use:

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error()); 

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    echo implode(",", $row)."\n";
}
header("Content-Type: text/csv");
header("Content-Disposition: attachment; filename=file.csv");

function outputCSV($data) {
  $output = fopen("php://output", "wb");
  foreach ($data as $row)
    fputcsv($output, $row); // here you can change delimiter/enclosure
  fclose($output);
}

outputCSV(array(
  array("name 1", "age 1", "city 1"),
  array("name 2", "age 2", "city 2"),
  array("name 3", "age 3", "city 3")
));

php: / /输出 函数

嘿它工作得很好....!!!!谢谢Peter Mortensen和Connor Burton

<?php
header("Content-type: application/csv");
header("Content-Disposition: attachment; filename=file.csv");
header("Pragma: no-cache");
header("Expires: 0");

ini_set('display_errors',1);
$private=1;
error_reporting(E_ALL ^ E_NOTICE);

mysql_connect("localhost", "user", "pass") or die(mysql_error());
mysql_select_db("db") or die(mysql_error());

$start = $_GET["start"];
$end = $_GET["end"];

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error());

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    $result.="{$row['email']},";
    $result.="\n";
    echo $result;
}

?>