我在MySQL数据库中有数据。我向用户发送一个URL,以获取他们的数据作为CSV文件。

我有链接的电子邮件,MySQL查询等覆盖。

当他们点击链接时,如何弹出从MySQL下载带有记录的CVS的窗口?

我已经有了所有能拿到唱片的资料。我只是不明白如何让PHP创建CSV文件,并让他们下载一个扩展名为. CSV的文件。


当前回答

下面是一个使用PDO并包含列标题的完整工作示例:

$query = $pdo->prepare('SELECT * FROM test WHERE id=?');
$query->execute(array($id));    
$results = $query->fetchAll(PDO::FETCH_ASSOC);
download_csv_results($results, 'test.csv'); 
exit();


function download_csv_results($results, $name)
{            
    header('Content-Type: text/csv');
    header('Content-Disposition: attachment; filename='. $name);
    header('Pragma: no-cache');
    header("Expires: 0");

    $outstream = fopen("php://output", "wb");    
    fputcsv($outstream, array_keys($results[0]));

    foreach($results as $result)
    {
        fputcsv($outstream, $result);
    }

    fclose($outstream);
}

其他回答

在$output变量中放入CSV数据,并返回正确的报头

header("Content-type: application/download\r\n");
header("Content-disposition: filename=filename.csv\r\n\r\n");
header("Content-Transfer-Encoding: ASCII\r\n");
header("Content-length: ".strlen($output)."\r\n");
echo $output;

首先将data作为String,以逗号作为分隔符(用“,”分隔)。就像这样

$CSV_string="No,Date,Email,Sender Name,Sender Email \n"; //making string, So "\n" is used for newLine

$rand = rand(1,50); //Make a random int number between 1 to 50.
$file ="export/export".$rand.".csv"; //For avoiding cache in the client and on the server 
                                     //side it is recommended that the file name be different.

file_put_contents($file,$CSV_string);

/* Or try this code if $CSV_string is an array
    fh =fopen($file, 'w');
    fputcsv($fh , $CSV_string , ","  , "\n" ); // "," is delimiter // "\n" is new line.
    fclose($fh);
*/

嘿它工作得很好....!!!!谢谢Peter Mortensen和Connor Burton

<?php
header("Content-type: application/csv");
header("Content-Disposition: attachment; filename=file.csv");
header("Pragma: no-cache");
header("Expires: 0");

ini_set('display_errors',1);
$private=1;
error_reporting(E_ALL ^ E_NOTICE);

mysql_connect("localhost", "user", "pass") or die(mysql_error());
mysql_select_db("db") or die(mysql_error());

$start = $_GET["start"];
$end = $_GET["end"];

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error());

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    $result.="{$row['email']},";
    $result.="\n";
    echo $result;
}

?>

最简单的方法是使用一个专门的CSV类,像这样:

$csv = new csv();
$csv->load_data(array(
    array('name'=>'John', 'age'=>35),
    array('name'=>'Adrian', 'age'=>23), 
    array('name'=>'William', 'age'=>57) 
));
$csv->send_file('age.csv'); 

要让它以CSV格式发送,并给出文件名,请使用header():

http://us2.php.net/header

header('Content-type: text/csv');
header('Content-disposition: attachment; filename="myfile.csv"');

至于创建CSV本身,您只需要遍历结果集,格式化输出并发送它,就像处理任何其他内容一样。