重写控制器Json/JsonResult以返回Json。Net:

这很有用

请看这个帖子:

http://forums.asp.net/p/1038457/1441866.aspx#1441866

基本上，虽然Date()格式是有效的javascript，但它不是有效的JSON(有区别)。如果您想要使用旧格式，您可能必须自己创建一个外观并转换值，或者找到一种方法来获取JsonResult中类型的序列化器，并让它使用日期的自定义格式。

不是没有原因，而是还有别的办法。首先，构造LINQ查询。然后，构造枚举结果的查询，并应用适合您的格式类型。

var query = from t in db.Table select new { t.DateField };
var result = from c in query.AsEnumerable() select new { c.DateField.toString("dd MMM yyy") };

我不得不说，额外的步骤很烦人，但效果很好。

让我们扩展一下casperOne的答案。

JSON规范没有说明Date值。MS不得不进行调用，他们选择的路径是利用javascript字符串表示中的一个小技巧:字符串字面量“/”与“\/”相同，字符串字面量永远不会被序列化为“\/”(甚至“\/”也必须映射为“\\/”)。

参见http://msdn.microsoft.com/en-us/library/bb299886.aspx#intro_to_json_topic2获得更好的解释(向下滚动到“从JavaScript文字到JSON”)

One of the sore points of JSON is the lack of a date/time literal. Many people are surprised and disappointed to learn this when they first encounter JSON. The simple explanation (consoling or not) for the absence of a date/time literal is that JavaScript never had one either: The support for date and time values in JavaScript is entirely provided through the Date object. Most applications using JSON as a data format, therefore, generally tend to use either a string or a number to express date and time values. If a string is used, you can generally expect it to be in the ISO 8601 format. If a number is used, instead, then the value is usually taken to mean the number of milliseconds in Universal Coordinated Time (UTC) since epoch, where epoch is defined as midnight January 1, 1970 (UTC). Again, this is a mere convention and not part of the JSON standard. If you are exchanging data with another application, you will need to check its documentation to see how it encodes date and time values within a JSON literal. For example, Microsoft's ASP.NET AJAX uses neither of the described conventions. Rather, it encodes .NET DateTime values as a JSON string, where the content of the string is /Date(ticks)/ and where ticks represents milliseconds since epoch (UTC). So November 29, 1989, 4:55:30 AM, in UTC is encoded as "\/Date(628318530718)\/".

一个解决办法就是把它解析出来:

value = new Date(parseInt(value.replace("/Date(", "").replace(")/",""), 10));

然而，我听说在某个地方有一个设置，可以让序列化器用新的Date(xxx)语法输出DateTime对象。我试着把它挖出来。

JSON.parse()的第二个参数接受一个恢复函数，其中规定了在返回值之前最初是如何生成值的。

下面是一个关于date的例子:

var parsed = JSON.parse(data, function(key, value) {
  if (typeof value === 'string') {
    var d = /\/Date\((\d*)\)\//.exec(value);
    return (d) ? new Date(+d[1]) : value;
  }
  return value;
});

查看JSON.parse()的文档

在页面中添加jquery UI插件。

function JsonDateFormate(dateFormate, jsonDateTime) {
    return $.datepicker.formatDate(dateFormate, eval('new ' + jsonDateTime.slice(1, -1)));
};

这不是最优雅的方式，但对我来说很管用:

var ms = date.substring(6, date.length - 2);
var newDate = formatDate(ms);


function formatDate(ms) {

    var date = new Date(parseInt(ms));
    var hour = date.getHours();
    var mins = date.getMinutes() + '';
    var time = "AM";

    // find time 
    if (hour >= 12) {
        time = "PM";
    }
    // fix hours format
    if (hour > 12) {
        hour -= 12;
    }
    else if (hour == 0) {
        hour = 12;
    }
    // fix minutes format
    if (mins.length == 1) {
        mins = "0" + mins;
    }
    // return formatted date time string
    return date.getMonth() + 1 + "/" + date.getDate() + "/" + date.getFullYear() + " " + hour + ":" + mins + " " + time;
}