你也可以从文本文件中读取文本到字符串，如下所示

string str = "";
StreamReader sr = new StreamReader(Application.StartupPath + "\\Sample.txt");
while(sr.Peek() != -1)
{
  str = str + sr.ReadLine();
}

File怎么样?ReadAllText:

string contents = File.ReadAllText(@"C:\temp\test.txt");

System.IO.StreamReader myFile =
   new System.IO.StreamReader("c:\\test.txt");
string myString = myFile.ReadToEnd();

string contents = System.IO.File.ReadAllText(path)

这是MSDN文档

你可以这样用

public static string ReadFileAndFetchStringInSingleLine(string file)
    {
        StringBuilder sb;
        try
        {
            sb = new StringBuilder();
            using (FileStream fs = File.Open(file, FileMode.Open))
            {
                using (BufferedStream bs = new BufferedStream(fs))
                {
                    using (StreamReader sr = new StreamReader(bs))
                    {
                        string str;
                        while ((str = sr.ReadLine()) != null)
                        {
                            sb.Append(str);
                        }
                    }
                }
            }
            return sb.ToString();
        }
        catch (Exception ex)
        {
            return "";
        }
    }

希望这对你有所帮助。

如果你想从应用程序的Bin文件夹中选择文件，那么你可以尝试以下操作，不要忘记做异常处理。

string content = File.ReadAllText(Path.Combine(System.IO.Directory.GetCurrentDirectory(), @"FilesFolder\Sample.txt"));