我有两个表达式的类型表达式<Func<T, bool>>和我想采取或,与或不是这些,并获得一个相同类型的新表达式

Expression<Func<T, bool>> expr1;
Expression<Func<T, bool>> expr2;

...

//how to do this (the code below will obviously not work)
Expression<Func<T, bool>> andExpression = expr AND expr2

当前回答

我需要实现相同的结果,但是使用一些更通用的东西(因为不知道类型)。多亏了marc的回答,我终于明白了我想要达到的目标:

    public static LambdaExpression CombineOr(Type sourceType, LambdaExpression exp, LambdaExpression newExp) 
    {
        var parameter = Expression.Parameter(sourceType);

        var leftVisitor = new ReplaceExpressionVisitor(exp.Parameters[0], parameter);
        var left = leftVisitor.Visit(exp.Body);

        var rightVisitor = new ReplaceExpressionVisitor(newExp.Parameters[0], parameter);
        var right = rightVisitor.Visit(newExp.Body);

        var delegateType = typeof(Func<,>).MakeGenericType(sourceType, typeof(bool));
        return Expression.Lambda(delegateType, Expression.Or(left, right), parameter);
    }

其他回答

我建议对PredicateBuilder和ExpressionVisitor解决方案再做一个改进。我把它叫做UnifyParametersByName,你可以在我的MIT库LinqExprHelper中找到它。它允许组合任意lambda表达式。通常问题是关于谓词表达式的,但是这个想法也可以扩展到投影表达式。

下面的代码使用了ExprAdres方法,它使用内联lambda创建了一个复杂的参数化表达式。这个复杂的表达式只编码一次,然后重用,这要感谢LinqExprHelper迷你库。

public IQueryable<UbezpExt> UbezpFull
{
    get
    {
        System.Linq.Expressions.Expression<
            Func<UBEZPIECZONY, UBEZP_ADRES, UBEZP_ADRES, UbezpExt>> expr =
            (u, parAdrM, parAdrZ) => new UbezpExt
            {
                Ub = u,
                AdrM = parAdrM,
                AdrZ = parAdrZ,
            };

        // From here an expression builder ExprAdres is called.
        var expr2 = expr
            .ReplacePar("parAdrM", ExprAdres("M").Body)
            .ReplacePar("parAdrZ", ExprAdres("Z").Body);
        return UBEZPIECZONY.Select((Expression<Func<UBEZPIECZONY, UbezpExt>>)expr2);
    }
}

这是子表达式的构建代码:

public static Expression<Func<UBEZPIECZONY, UBEZP_ADRES>> ExprAdres(string sTyp)
{
    return u => u.UBEZP_ADRES.Where(a => a.TYP_ADRESU == sTyp)
        .OrderByDescending(a => a.DATAOD).FirstOrDefault();
}

我试图实现的是执行参数化查询,而不需要复制粘贴,并能够使用内联lambdas,这非常漂亮。如果没有这些帮助表达式,我将被迫一次性创建整个查询。

我在这里组合了一些漂亮的答案,以便能够轻松地支持更多的表达式操作符。

这是基于@Dejan的回答,但现在添加OR也很容易。我选择不将Combine函数设为公共的,但是您可以这样做,以便更加灵活。

public static class ExpressionExtensions
{
    public static Expression<Func<T, bool>> AndAlso<T>(this Expression<Func<T, bool>> leftExpression,
        Expression<Func<T, bool>> rightExpression) =>
        Combine(leftExpression, rightExpression, Expression.AndAlso);

    public static Expression<Func<T, bool>> Or<T>(this Expression<Func<T, bool>> leftExpression,
        Expression<Func<T, bool>> rightExpression) =>
        Combine(leftExpression, rightExpression, Expression.Or);

    public static Expression<Func<T, bool>> Combine<T>(Expression<Func<T, bool>> leftExpression, Expression<Func<T, bool>> rightExpression, Func<Expression, Expression, BinaryExpression> combineOperator)
    {
        var leftParameter = leftExpression.Parameters[0];
        var rightParameter = rightExpression.Parameters[0];

        var visitor = new ReplaceParameterVisitor(rightParameter, leftParameter);

        var leftBody = leftExpression.Body;
        var rightBody = visitor.Visit(rightExpression.Body);

        return Expression.Lambda<Func<T, bool>>(combineOperator(leftBody, rightBody), leftParameter);
    }

    private class ReplaceParameterVisitor : ExpressionVisitor
    {
        private readonly ParameterExpression _oldParameter;
        private readonly ParameterExpression _newParameter;

        public ReplaceParameterVisitor(ParameterExpression oldParameter, ParameterExpression newParameter)
        {
            _oldParameter = oldParameter;
            _newParameter = newParameter;
        }

        protected override Expression VisitParameter(ParameterExpression node)
        {
            return ReferenceEquals(node, _oldParameter) ? _newParameter : base.VisitParameter(node);
        }
    }
}

用法没有改变,仍然是这样的:

Expression<Func<Result, bool>> noFilterExpression = item => filters == null;

Expression<Func<Result, bool>> laptopFilterExpression = item => item.x == ...
Expression<Func<Result, bool>> dateFilterExpression = item => item.y == ...

var combinedFilterExpression = noFilterExpression.Or(laptopFilterExpression.AndAlso(dateFilterExpression));
    
efQuery.Where(combinedFilterExpression);

(这是一个基于我的实际代码的示例,但将其视为伪代码)

这里没有什么新东西,只是把这个答案和这个答案结合起来,稍微重构了一下,这样即使是我也能理解发生了什么:

public static class ExpressionExtensions
{
    public static Expression<Func<T, bool>> AndAlso<T>(this Expression<Func<T, bool>> expr1, Expression<Func<T, bool>> expr2)
    {
        ParameterExpression parameter1 = expr1.Parameters[0];
        var visitor = new ReplaceParameterVisitor(expr2.Parameters[0], parameter1);
        var body2WithParam1 = visitor.Visit(expr2.Body);
        return Expression.Lambda<Func<T, bool>>(Expression.AndAlso(expr1.Body, body2WithParam1), parameter1);
    }

    private class ReplaceParameterVisitor : ExpressionVisitor
    {
        private ParameterExpression _oldParameter;
        private ParameterExpression _newParameter;

        public ReplaceParameterVisitor(ParameterExpression oldParameter, ParameterExpression newParameter)
        {
            _oldParameter = oldParameter;
            _newParameter = newParameter;
        }

        protected override Expression VisitParameter(ParameterExpression node)
        {
            if (ReferenceEquals(node, _oldParameter))
                return _newParameter;

            return base.VisitParameter(node);
        }
    }
}
using System;
using System.Linq.Expressions;

namespace Extensions
{


    public class Example
    {
        //How to use it
        public static void Main()
        {
            Expression<Func<string, bool>> expression1 = exp => true;
            Expression<Func<string, bool>> expression2 = exp => false;

            Expression<Func<string, bool>> expression3 = ExpressionExtensions.AndAlso(expression1, expression2);
            Expression<Func<string, bool>> expression4 = ExpressionExtensions.OrElse(expression1, expression2);

            Expression<Func<string, bool>> expression = ExpressionExtensions.AndAlso(expression3, expression4);
        }
    }


    public static class ExpressionExtensions
    {
        public static Expression<Func<T, bool>> AndAlso<T>(this Expression<Func<T, bool>> expr1, Expression<Func<T, bool>> expr2)
        {
            ParameterExpression parameter1 = expr1.Parameters[0];
            var visitor = new ReplaceParameterVisitor(expr2.Parameters[0], parameter1);
            var body2WithParam1 = visitor.Visit(expr2.Body);
            return Expression.Lambda<Func<T, bool>>(Expression.AndAlso(expr1.Body, body2WithParam1), parameter1);
        }

        public static Expression<Func<T, bool>> OrElse<T>(this Expression<Func<T, bool>> expr1, Expression<Func<T, bool>> expr2)
        {
            ParameterExpression parameter1 = expr1.Parameters[0];
            var visitor = new ReplaceParameterVisitor(expr2.Parameters[0], parameter1);
            var body2WithParam1 = visitor.Visit(expr2.Body);
            return Expression.Lambda<Func<T, bool>>(Expression.OrElse(expr1.Body, body2WithParam1), parameter1);
        }

        private class ReplaceParameterVisitor : ExpressionVisitor
        {
            private readonly ParameterExpression _oldParameter;
            private readonly ParameterExpression _newParameter;

            public ReplaceParameterVisitor(ParameterExpression oldParameter, ParameterExpression newParameter)
            {
                _oldParameter = oldParameter;
                _newParameter = newParameter;
            }

            protected override Expression VisitParameter(ParameterExpression node)
            {
                if (ReferenceEquals(node, _oldParameter))
                    return _newParameter;

                return base.VisitParameter(node);
            }
        }
    }
}

你可以使用表达式。和also / OrElse组合逻辑表达式,但你必须确保参数表达式是相同的。

我遇到了EF和PredicateBuilder的麻烦,所以我做了自己的而不诉诸Invoke,我可以像这样使用:

var filterC = filterA.And(filterb);

我的PredicateBuilder的源代码:

public static class PredicateBuilder {

    public static Expression<Func<T, bool>> And<T>(this Expression<Func<T, bool>> a, Expression<Func<T, bool>> b) {    

        ParameterExpression p = a.Parameters[0];

        SubstExpressionVisitor visitor = new SubstExpressionVisitor();
        visitor.subst[b.Parameters[0]] = p;

        Expression body = Expression.AndAlso(a.Body, visitor.Visit(b.Body));
        return Expression.Lambda<Func<T, bool>>(body, p);
    }

    public static Expression<Func<T, bool>> Or<T>(this Expression<Func<T, bool>> a, Expression<Func<T, bool>> b) {    

        ParameterExpression p = a.Parameters[0];

        SubstExpressionVisitor visitor = new SubstExpressionVisitor();
        visitor.subst[b.Parameters[0]] = p;

        Expression body = Expression.OrElse(a.Body, visitor.Visit(b.Body));
        return Expression.Lambda<Func<T, bool>>(body, p);
    }   
}

和实用工具类来替换lambda中的参数:

internal class SubstExpressionVisitor : System.Linq.Expressions.ExpressionVisitor {
        public Dictionary<Expression, Expression> subst = new Dictionary<Expression, Expression>();

        protected override Expression VisitParameter(ParameterExpression node) {
            Expression newValue;
            if (subst.TryGetValue(node, out newValue)) {
                return newValue;
            }
            return node;
        }
    }