如何从数组中删除一个特定值? 类似 :
array.remove(value);
制约:我必须使用核心 JavaScript 。 框架不允许 。
如何从数组中删除一个特定值? 类似 :
array.remove(value);
制约:我必须使用核心 JavaScript 。 框架不允许 。
当前回答
您只需要按元素或索引过滤 :
var num = [5, 6, 5, 4, 5, 1, 5]; var result1 = num.filter((el, index) => el != 5) // for remove all 5 var result2 = num.filter((el, index) => index != 5) // for remove item with index == 5 console.log(result1); console.log(result2);
其他回答
很简单,只要做:
var arr = [1,2,4,5];
arr.splice(arr.indexOf(5), 1);
console.log(arr); // [1,2,4];
您可以对每个数组项进行循环, 如果在您的数组中存在的话, 可以复制并连接它 。
function destroy(arr, val) {
for (var i = 0; i < arr.length; i++) if (arr[i] === val) arr.splice(i, 1);
return arr;
}
根据索引删除
函数返回在索引中没有元素的数组副本 :
/**
* removeByIndex
* @param {Array} array
* @param {Number} index
*/
function removeByIndex(array, index){
return array.filter(function(elem, _index){
return index != _index;
});
}
l = [1,3,4,5,6,7];
console.log(removeByIndex(l, 1));
$> [ 1, 4, 5, 6, 7 ]
以值删除
函数返回没有值的数组副本。
/**
* removeByValue
* @param {Array} array
* @param {Number} value
*/
function removeByValue(array, value){
return array.filter(function(elem, _index){
return value != elem;
});
}
l = [1,3,4,5,6,7];
console.log(removeByValue(l, 5));
$> [ 1, 3, 4, 6, 7]
Vanilla JavaScript(ES5.1) - 已建立版本
浏览器支持: Internet Explorer 9 或后( 详细浏览器支持)
/**
* Removes all occurences of the item from the array.
*
* Modifies the array “in place”, i.e. the array passed as an argument
* is modified as opposed to creating a new array. Also returns the modified
* array for your convenience.
*/
function removeInPlace(array, item) {
var foundIndex, fromIndex;
// Look for the item (the item can have multiple indices)
fromIndex = array.length - 1;
foundIndex = array.lastIndexOf(item, fromIndex);
while (foundIndex !== -1) {
// Remove the item (in place)
array.splice(foundIndex, 1);
// Bookkeeping
fromIndex = foundIndex - 1;
foundIndex = array.lastIndexOf(item, fromIndex);
}
// Return the modified array
return array;
}
Vanilla JavaScript(ES5.1) - 永恒版本
浏览器支持: 与原版的香草 JavaScript 相同
/**
* Removes all occurences of the item from the array.
*
* Returns a new array with all the items of the original array except
* the specified item.
*/
function remove(array, item) {
var arrayCopy;
arrayCopy = array.slice();
return removeInPlace(arrayCopy, item);
}
Vanilla ES6 - 永恒版本
浏览器支持: Chrome 46, 边缘 12, Firefox 16, Opera 37, Safari 8 (详细浏览器支持)
/**
* Removes all occurences of the item from the array.
*
* Returns a new array with all the items of the original array except
* the specified item.
*/
function remove(array, item) {
// Copy the array
array = [...array];
// Look for the item (the item can have multiple indices)
let fromIndex = array.length - 1;
let foundIndex = array.lastIndexOf(item, fromIndex);
while (foundIndex !== -1) {
// Remove the item by generating a new array without it
array = [
...array.slice(0, foundIndex),
...array.slice(foundIndex + 1),
];
// Bookkeeping
fromIndex = foundIndex - 1;
foundIndex = array.lastIndexOf(item, fromIndex)
}
// Return the new array
return array;
}
我张贴我的代码,删除一个阵列元素, 并缩短阵列长度 。
function removeElement(idx, arr) {
// Check the index value
if (idx < 0 || idx >= arr.length) {
return;
}
// Shift the elements
for (var i = idx; i > 0; --i) {
arr[i] = arr[i - 1];
}
// Remove the first element in array
arr.shift();
}