一个内联的简单方法就是添加bdays。在删除按钮中拼接($index, 1)。

  <ul ng-repeat="bday in bdays">
  <li>
    <span ng-hide="editing" ng-click="editing = true">{{bday.name}} | {{bday.date}}</span>
    <form ng-show="editing" ng-submit="editing = false">
      <label>Name:</label>
      <input type="text" ng-model="bday.name" placeholder="Name" ng-required/>
      <label>Date:</label>
      <input type="date" ng-model="bday.date" placeholder="Date" ng-required/>
      <br/>
      <button class="btn" type="submit">Save</button>
      <a class="btn" ng-click="bdays.splice($index, 1)">Delete</a>
    </form>
  </li>
</ul>

使用$index在基本情况下工作得非常好，@charlietfl的答案很棒。但有时，$index是不够的。

Imagine you have a single array, which you're presenting in two different ng-repeat's. One of those ng-repeat's is filtered for objects that have a truthy property, and the other is filtered for a falsy property. Two different filtered arrays are being presented, which derive from a single original array. (Or, if it helps to visualize: perhaps you have a single array of people, and you want one ng-repeat for the women in that array, and another for the men in that same array.) Your goal: delete reliably from the original array, using information from the members of the filtered arrays.

在每个过滤后的数组中，$index不会是原始数组中该项的索引。它将是筛选子数组的下标。你无法在原始的people数组中知道person的索引，你只能从women或men子数组中知道$index。尝试使用它删除，你会有项目从任何地方消失，除了你想要的地方。怎么办呢?

如果您足够幸运，使用的数据模型包含每个对象的唯一标识符，那么使用该标识符而不是$index来查找对象并将其从主数组中拼接出来。(请使用下面的例子，但是使用唯一标识符。)但如果你没那么幸运呢?

Angular实际上用一个名为$$hashKey的唯一属性来扩充ng-repeat数组(主数组中的原始数组)中的每一项。您可以在原始数组中搜索与要删除的项的$$hashKey相匹配的项，并以这种方式删除它。

注意$$hashKey是一个实现细节，不包含在ng-repeat的已发布API中。他们可以在任何时候删除对该属性的支持。但可能不会。: -)

$scope.deleteFilteredItem = function(hashKey, sourceArray){
  angular.forEach(sourceArray, function(obj, index){
    // sourceArray is a reference to the original array passed to ng-repeat, 
    // rather than the filtered version. 
    // 1. compare the target object's hashKey to the current member of the iterable:
    if (obj.$$hashKey === hashKey) {
      // remove the matching item from the array
      sourceArray.splice(index, 1);
      // and exit the loop right away
      return;
    };
  });
}

调用:

ng-click="deleteFilteredItem(item.$$hashKey, refToSourceArray)"

EDIT:使用这样的函数(键在$$hashKey上，而不是特定于模型的属性名上)还有一个显著的附加优势，即使该函数可以跨不同的模型和上下文重用。向它提供数组引用和项引用，它就可以工作了。

以防你在ng-repeat里

你可以选择一条线

    <div ng-repeat="key in keywords"> 
        <button ng-click="keywords.splice($index, 1)">

            {{key.name}}
        </button>
    </div>

$index被angular用来显示ng-repeat中数组的当前索引

建立在接受的答案，这将与ngRepeat，过滤器和处理期望更好:

控制器:

vm.remove = function(item, array) {
  var index = array.indexOf(item);
  if(index>=0)
    array.splice(index, 1);
}

观点:

ng-click="vm.remove(item,$scope.bdays)"

一个内联的简单方法就是添加bdays。在删除按钮中拼接($index, 1)。

  <ul ng-repeat="bday in bdays">
  <li>
    <span ng-hide="editing" ng-click="editing = true">{{bday.name}} | {{bday.date}}</span>
    <form ng-show="editing" ng-submit="editing = false">
      <label>Name:</label>
      <input type="text" ng-model="bday.name" placeholder="Name" ng-required/>
      <label>Date:</label>
      <input type="date" ng-model="bday.date" placeholder="Date" ng-required/>
      <br/>
      <button class="btn" type="submit">Save</button>
      <a class="btn" ng-click="bdays.splice($index, 1)">Delete</a>
    </form>
  </li>
</ul>

以下是正确答案:

<a class="btn" ng-click="remove($index)">Delete</a>
$scope.remove=function($index){ 
  $scope.bdays.splice($index,1);     
}

在@charlietfl的回答中。我认为这是错误的，因为你传递$index作为参数，但你在控制器中使用愿望。如果我说错了请指正:)