在Python中是否有goto或任何等价的东西能够跳转到特定的代码行?
当前回答
现在有了。转到
我想这可能对你要找的东西有用。
其他回答
一个工作版本已经完成:http://entrian.com/goto/。
注:这是一个愚人节玩笑。(工作)
# Example 1: Breaking out from a deeply nested loop:
from goto import goto, label
for i in range(1, 10):
for j in range(1, 20):
for k in range(1, 30):
print i, j, k
if k == 3:
goto .end
label .end
print "Finished\n"
不用说。是的,它很有趣,但不要使用它。
不,Python不支持标签和goto。它是一种高度结构化的编程语言。
我想要同样的答案,我不想使用goto。所以我使用了下面的例子(来自learnpythonthehardway)
def sample():
print "This room is full of gold how much do you want?"
choice = raw_input("> ")
how_much = int(choice)
if "0" in choice or "1" in choice:
check(how_much)
else:
print "Enter a number with 0 or 1"
sample()
def check(n):
if n < 150:
print "You are not greedy, you win"
exit(0)
else:
print "You are nuts!"
exit(0)
现在有了。转到
我想这可能对你要找的东西有用。
我认为while循环是“goto_Statement”的替代。因为3.6之后,goto循环不再工作了。我还写了一个while循环的例子。
str1 = "stop"
while str1 == "back":
var1 = int(input(" Enter Ist Number: "))
var2 = int(input(" Enter 2nd Number: "))
var3 = print(""" What is your next operation
For Addition Press And Enter : 'A'
For Muliplt Press And Enter : 'M'
For Division Press And Enter : 'D'
For Subtaction Press And Enter : 'S' """)
var4 = str(input("For operation press any number : "))
if(var1 == 45) and (var2 == 3):
print("555")
elif(var1 == 56) and (var2 == 9):
print("77")
elif(var1 == 56) and (var2 == 6):
print("4")
else:
if(var4 == "A" or "a"):
print(var1 + var2)
if(var4 == "M" or "m"):
print(var1 * var2)
if(var4 == "D" or "d"):
print(var1 / var2)
if(var4 == "S" or "s"):
print(var1 - var2)
print("if you want to continue then type 'stop'")
str1 = input()
print("Strt again")