在Python中是否有goto或任何等价的东西能够跳转到特定的代码行?


当前回答

现在有了。转到

我想这可能对你要找的东西有用。

其他回答

一个工作版本已经完成:http://entrian.com/goto/。

注:这是一个愚人节玩笑。(工作)

# Example 1: Breaking out from a deeply nested loop:
from goto import goto, label

for i in range(1, 10):
    for j in range(1, 20):
        for k in range(1, 30):
            print i, j, k
            if k == 3:
                goto .end
label .end
print "Finished\n"

不用说。是的,它很有趣,但不要使用它。

不,Python不支持标签和goto。它是一种高度结构化的编程语言。

我想要同样的答案,我不想使用goto。所以我使用了下面的例子(来自learnpythonthehardway)

def sample():
    print "This room is full of gold how much do you want?"
    choice = raw_input("> ")
    how_much = int(choice)
    if "0" in choice or "1" in choice:
        check(how_much)
    else:
        print "Enter a number with 0 or 1"
        sample()

def check(n):
    if n < 150:
        print "You are not greedy, you win"
        exit(0)
    else:
        print "You are nuts!"
        exit(0)

现在有了。转到

我想这可能对你要找的东西有用。

我认为while循环是“goto_Statement”的替代。因为3.6之后,goto循环不再工作了。我还写了一个while循环的例子。

str1 = "stop"
while str1 == "back":
    var1 = int(input(" Enter Ist Number: "))
    var2 = int(input(" Enter 2nd Number: "))
    var3 = print("""  What is your next operation
                      For Addition   Press And Enter : 'A'
                      For Muliplt    Press And Enter : 'M'
                      For Division   Press And Enter : 'D'
                      For Subtaction Press And Enter : 'S' """)

    var4 = str(input("For operation press any number : "))
    if(var1 == 45) and (var2 == 3):
        print("555")
    elif(var1 == 56) and (var2 == 9):
        print("77")
    elif(var1 == 56) and (var2 == 6):
        print("4")
    else:
        if(var4 == "A" or "a"):
            print(var1 + var2)
        if(var4 == "M" or "m"):
            print(var1 * var2)
        if(var4 == "D" or "d"):
            print(var1 / var2)
        if(var4 == "S" or "s"):
            print(var1 - var2)

    print("if you want to continue then type  'stop'")

    str1 = input()
print("Strt again")