无效的回发或回调参数。使用'<pages enableEventValidation="true"/>'启用事件验证

当我从客户端返回一个页面时，我得到以下错误。我有JavaScript代码，修改asp:ListBox在客户端。

我们如何解决这个问题?

错误详情如下:

Server Error in '/XXX' Application.

--------------------------------------------------------------------------------
Invalid postback or callback argument.  Event validation is enabled using <pages enableEventValidation="true"/> in configuration or <%@ Page EnableEventValidation="true" %> in a page.  For security purposes, this feature verifies that arguments to postback or callback events originate from the server control that originally rendered them.  If the data is valid and expected, use the ClientScriptManager.RegisterForEventValidation method in order to register the postback or callback data for validation.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.ArgumentException: Invalid postback or callback argument.  Event validation is enabled using <pages enableEventValidation="true"/> in configuration or <%@ Page EnableEventValidation="true" %> in a page.  For security purposes, this feature verifies that arguments to postback or callback events originate from the server control that originally rendered them.  If the data is valid and expected, use the ClientScriptManager.RegisterForEventValidation method in order to register the postback or callback data for validation.

Source Error:

An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.

Stack Trace:

[ArgumentException: Invalid postback or callback argument.  Event validation is enabled using <pages enableEventValidation="true"/> in configuration or <%@ Page EnableEventValidation="true" %> in a page.  For security purposes, this feature verifies that arguments to postback or callback events originate from the server control that originally rendered them.  If the data is valid and expected, use the ClientScriptManager.RegisterForEventValidation method in order to register the postback or callback data for validation.]
   System.Web.UI.ClientScriptManager.ValidateEvent(String uniqueId, String argument) +2132728
   System.Web.UI.Control.ValidateEvent(String uniqueID, String eventArgument) +108
   System.Web.UI.WebControls.ListBox.LoadPostData(String postDataKey, NameValueCollection postCollection) +274
   System.Web.UI.WebControls.ListBox.System.Web.UI.IPostBackDataHandler.LoadPostData(String postDataKey, NameValueCollection postCollection) +11
   System.Web.UI.Page.ProcessPostData(NameValueCollection postData, Boolean fBeforeLoad) +353
   System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1194

--------------------------------------------------------------------------------
Version Information: Microsoft .NET Framework Version:2.0.50727.1433; ASP.NET Version:2.0.50727.1433

当前回答

在客户端使用JavaScript修改ListBox时，我也遇到了同样的问题。当您从客户端向ListBox添加页面呈现时不存在的新项时，就会发生这种情况。

我找到的修复方法是通知事件验证系统可以从客户端添加所有可能的有效项。您可以通过重写Page来实现这一点。渲染并调用Page.ClientScript.RegisterForEventValidation为你的JavaScript可以添加到列表框的每个值:

protected override void Render(HtmlTextWriter writer)
{
    foreach (string val in allPossibleListBoxValues)
    {
        Page.ClientScript.RegisterForEventValidation(myListBox.UniqueID, val);
    }
    base.Render(writer);
}

如果列表框有大量潜在的有效值，这可能有点麻烦。在我的例子中，我在两个listbox之间移动项目——一个有所有可能的值，另一个最初是空的，但当用户单击按钮时，在JavaScript中用第一个值的子集填充。在这种情况下，你只需要遍历第一个列表框中的项目，并将每个项目注册到第二个列表框中:

protected override void Render(HtmlTextWriter writer)
{
    foreach (ListItem i in listBoxAll.Items)
    {
        Page.ClientScript.RegisterForEventValidation(listBoxSelected.UniqueID, i.Value);
    }
    base.Render(writer);
}

2011-10-13 06:25:29

其他回答

供参考，我有同样的错误消息的问题，这是我在同一页上有2个表单标签。一个在母版页，一个在页面本身。一旦我删除了第二个形式标签对，问题就消失了。

2015-03-11 17:12:10

我实现了一个嵌套的网格视图，我也遇到了同样的问题。我使用了LinkButton而不是像这样的图像按钮:

在我有这样的专栏之前:

<asp:TemplateField ItemStyle-Width="9">
  <ItemTemplate>
 <asp:ImageButton ID="ImgBtn" ImageUrl="Include/images/gridplus.gif" CommandName="Expand"
                        runat="server" />
  </ItemTemplate>
</asp:TemplateField>

我像这样替换了。

<asp:TemplateField>
<ItemTemplate>
     <asp:LinkButton  CommandName="Expand" ID="lnkBtn"  runat="server" ><asp:Image  ID="Img"  runat="server" ImageUrl="~/Images/app/plus.gif" /></asp:LinkButton>
      </ItemTemplate>
</asp:TemplateField>

2011-04-21 12:34:03

如果您通过客户端脚本填写下拉列表，则在将表单提交回服务器之前清除列表;然后ASP。NET将不会抱怨，安全性将仍然存在。

为了从DDL中获得选择的数据，您可以将“OnChange”事件附加到DDL以收集隐藏输入或文本框中的值，并使用Style="display: none;"

2008-12-11 20:43:00

(1) EnableEventValidation = " false "...................这对我没用。

(2) ClientScript.RegisterForEventValidation……这对我没用。

解决方案1:

在GridView中将Button/ImageButton更改为LinkButton。它的工作原理。(但我喜欢ImageButton)

研究:Button/ImageButton和LinkButton使用不同的回发方法

原文:

http://geekswithblogs.net/mahesh/archive/2006/06/27/83264.aspx

解决方案2:

在OnInit()中，输入如下代码来设置Button/ImageButton的唯一ID:

protected override void OnInit(EventArgs e) {
  foreach (GridViewRow grdRw in gvEvent.Rows) {

  Button deleteButton = (Button)grdRw.Cells[2].Controls[1];

  deleteButton.ID = "btnDelete_" + grdRw.RowIndex.ToString();           
  }
}

原文:

http://www.c-sharpcorner.com/Forums/Thread/35301/

2013-03-30 02:58:11

此错误将在没有回发的情况下显示

添加代码:

If(!IsPostBack){

 //do something

}

2013-12-26 15:03:03

无效的回发或回调参数。使用'<pages enableEventValidation="true"/>'启用事件验证

推荐文章

最新文章

标签