.shuffle()和.shuffled()是Swift的一部分


原历史问题:

我如何随机或洗牌在Swift数组中的元素?例如,如果我的数组包含52张扑克牌,我想要洗牌数组以洗牌牌组。


当前回答

在Swift 2.0中,GameplayKit可能会来拯救你!(iOS9或更高版本支持)

import GameplayKit

func shuffle() {
    array = GKRandomSource.sharedRandom().arrayByShufflingObjectsInArray(array)
}

其他回答

这是一些在playground上运行的代码。你不需要在实际的Xcode项目中导入Darwin。

import darwin

var a = [1,2,3,4,5,6,7]

func shuffle<ItemType>(item1: ItemType, item2: ItemType) -> Bool {
    return drand48() > 0.5
}

sort(a, shuffle)

println(a)

你也可以使用通用交换函数,实现前面提到的Fisher-Yates:

for idx in 0..<arr.count {
  let rnd = Int(arc4random_uniform(UInt32(idx)))
  if rnd != idx {
    swap(&arr[idx], &arr[rnd])
  }
}

或者更简洁:

for idx in 0..<steps.count {
  swap(&steps[idx], &steps[Int(arc4random_uniform(UInt32(idx)))])
}

SWIFT 4

func createShuffledSequenceOfNumbers(max:UInt)->[UInt] {

    var array:[UInt]! = []
    var myArray:[UInt]! = []
    for i in 1...max {
        myArray.append(i)
    }
    for i in 1...max {
        array.append(i)
    }
    var tempArray:[Int]! = []
    for index in 0...(myArray.count - 1) {

        var isNotFinded:Bool = true
        while(isNotFinded){

            let randomNumber = arc4random_uniform(UInt32(myArray.count))
            let randomIndex = Int(randomNumber)

            if(!tempArray.contains(randomIndex)){
                tempArray.append(randomIndex)

                array[randomIndex] = myArray[index]
                isNotFinded = false
            }
        }
    }

    return array
}

如果你想使用简单的Swift For循环函数,使用这个->

var arrayItems = ["A1", "B2", "C3", "D4", "E5", "F6", "G7", "H8", "X9", "Y10", "Z11"]
var shuffledArray = [String]()

for i in 0..<arrayItems.count
{
    let randomObject = Int(arc4random_uniform(UInt32(items.count)))

    shuffledArray.append(items[randomObject])

    items.remove(at: randomObject)
}

print(shuffledArray)

Swift Array使用扩展名->

extension Array {
    // Order Randomize
    mutating func shuffle() {
        for _ in 0..<count {
            sort { (_,_) in arc4random() < arc4random() }
        }
    }
}

这是如何在Swift 3.0中洗牌一个种子数组。

extension MutableCollection where Indices.Iterator.Element == Index {
    mutating func shuffle() {
        let c = count
        guard c > 1 else { return }


        for (firstUnshuffled , unshuffledCount) in zip(indices, stride(from: c, to: 1, by: -1)) {
            srand48(seedNumber)
            let number:Int = numericCast(unshuffledCount)
            let r = floor(drand48() * Double(number))

            let d: IndexDistance = numericCast(Int(r))
            guard d != 0 else { continue }
            let i = index(firstUnshuffled, offsetBy: d)
            swap(&self[firstUnshuffled], &self[i])
        }
    }
}