为了避免显式检查'yes'的这些变体，你可以使用bash正则表达式操作符'=~'和一个正则表达式:

read -p "Are you sure you want to continue? <y/N> " prompt
if [[ $prompt =~ [yY](es)* ]]
then
(etc...)

它测试用户输入是否以“y”或“y”开头，后面是0个或多个“es”。

不需要按enter

这里有一个更长的，但可重用的模块化方法:

返回0=yes和1=no 不需要按enter键-只需一个字符 可以按enter键接受默认选择吗 可以禁用默认选择来强制选择吗 适用于zsh和bash。

按enter键时默认为“no”

注意，N是大写的。此处按下enter键，接受默认值:

$ confirm "Show dangerous command" && echo "rm *"
Show dangerous command [y/N]?

还要注意，[y/N]?被自动追加。 默认的“no”被接受，所以什么都不回显。

重新提示，直到给出有效的响应:

$ confirm "Show dangerous command" && echo "rm *"
Show dangerous command [y/N]? X
Show dangerous command [y/N]? y
rm *

按enter键时默认为“yes”

注意，Y是大写的:

$ confirm_yes "Show dangerous command" && echo "rm *"
Show dangerous command [Y/n]?
rm *

上面，我只是按了回车键，命令就运行了。

输入- require y或n时无默认值

$ get_yes_keypress "Here you cannot press enter. Do you like this"
Here you cannot press enter. Do you like this [y/n]? k
Here you cannot press enter. Do you like this [y/n]?
Here you cannot press enter. Do you like this [y/n]? n
$ echo $?
1

这里返回1或false。注意[y/n]没有大写?

Code

# Read a single char from /dev/tty, prompting with "$*"
# Note: pressing enter will return a null string. Perhaps a version terminated with X and then remove it in caller?
# See https://unix.stackexchange.com/a/367880/143394 for dealing with multi-byte, etc.
function get_keypress {
  local REPLY IFS=
  >/dev/tty printf '%s' "$*"
  [[ $ZSH_VERSION ]] && read -rk1  # Use -u0 to read from STDIN
  # See https://unix.stackexchange.com/q/383197/143394 regarding '\n' -> ''
  [[ $BASH_VERSION ]] && </dev/tty read -rn1
  printf '%s' "$REPLY"
}

# Get a y/n from the user, return yes=0, no=1 enter=$2
# Prompt using $1.
# If set, return $2 on pressing enter, useful for cancel or defualting
function get_yes_keypress {
  local prompt="${1:-Are you sure} [y/n]? "
  local enter_return=$2
  local REPLY
  # [[ ! $prompt ]] && prompt="[y/n]? "
  while REPLY=$(get_keypress "$prompt"); do
    [[ $REPLY ]] && printf '\n' # $REPLY blank if user presses enter
    case "$REPLY" in
      Y|y)  return 0;;
      N|n)  return 1;;
      '')   [[ $enter_return ]] && return "$enter_return"
    esac
  done
}
    
# Credit: http://unix.stackexchange.com/a/14444/143394
# Prompt to confirm, defaulting to NO on <enter>
# Usage: confirm "Dangerous. Are you sure?" && rm *
function confirm {
  local prompt="${*:-Are you sure} [y/N]? "
  get_yes_keypress "$prompt" 1
}    

# Prompt to confirm, defaulting to YES on <enter>
function confirm_yes {
  local prompt="${*:-Are you sure} [Y/n]? "
  get_yes_keypress "$prompt" 0
}

为了避免显式检查'yes'的这些变体，你可以使用bash正则表达式操作符'=~'和一个正则表达式:

read -p "Are you sure you want to continue? <y/N> " prompt
if [[ $prompt =~ [yY](es)* ]]
then
(etc...)

它测试用户输入是否以“y”或“y”开头，后面是0个或多个“es”。

这个版本允许你有不止一种情况y或y n或n

Optionally: Repeat the question until an approve question is provided Optionally: Ignore any other answer Optionally: Exit the terminal if you want confirm() { echo -n "Continue? y or n? " read REPLY case $REPLY in [Yy]) echo 'yup y' ;; # you can change what you do here for instance [Nn]) break ;; # exit case statement gracefully # Here are a few optional options to choose between # Any other answer: # 1. Repeat the question *) confirm ;; # 2. ignore # *) ;; # 3. Exit terminal # *) exit ;; esac # REPLY='' }

还要注意:在这个函数的最后一行清除REPLY变量。否则，如果你回显$REPLY，你会看到它仍然设置，直到你打开或关闭你的终端或再次设置它。

这可能有点太短了，但对于我自己的私人使用，它工作得很好

read -n 1 -p "Push master upstream? [Y/n] " reply; 
if [ "$reply" != "" ]; then echo; fi
if [ "$reply" = "${reply#[Nn]}" ]; then
    git push upstream master
fi

read -n 1只读取一个字符。不需要按回车键。如果不是“n”或“n”，则假定是“Y”。按回车键也意味着Y。

(至于真正的问题:使它成为一个bash脚本，并更改您的别名指向该脚本，而不是之前所指向的内容)

以下是您需要的大致片段。 让我看看如何转发这些论点。

read -p "Are you sure you want to continue? <y/N> " prompt
if [[ $prompt == "y" || $prompt == "Y" || $prompt == "yes" || $prompt == "Yes" ]]
then
  # http://stackoverflow.com/questions/1537673/how-do-i-forward-parameters-to-other-command-in-bash-script
else
  exit 0
fi

注意这里的yes |命令名:)