在嵌套对象中，在React with Hooks中更新状态的正确方法是什么?
export Example = () => {
const [exampleState, setExampleState] = useState(
{masterField: {
fieldOne: "a",
fieldTwo: {
fieldTwoOne: "b"
fieldTwoTwo: "c"
}
}
})
如何使用setExampleState将exampleState更新为a(附加字段)?
const a = {
masterField: {
fieldOne: "a",
fieldTwo: {
fieldTwoOne: "b",
fieldTwoTwo: "c"
}
},
masterField2: {
fieldOne: "c",
fieldTwo: {
fieldTwoOne: "d",
fieldTwoTwo: "e"
}
},
}
}
b(改变值)?
const b = {masterField: {
fieldOne: "e",
fieldTwo: {
fieldTwoOne: "f"
fieldTwoTwo: "g"
}
}
})
您必须使用Rest参数和扩展语法(https://javascript.info/rest-parameters-spread)，并设置一个以preState作为setState参数的函数。
不起作用(功能缺失)
[state, setState] = useState({})
const key = 'foo';
const value = 'bar';
setState({
...state,
[key]: value
});
确实工作!
[state, setState] = useState({})
const key = 'foo';
const value = 'bar';
setState(prevState => ({
...prevState,
[key]: value
}));
我迟到了。：）
@aseferov回答在意图是重新进入整个对象结构时非常有效。然而，如果目标/目标是更新Object中的特定字段值，我认为下面的方法更好。
情境:
const [infoData, setInfoData] = useState({
major: {
name: "John Doe",
age: "24",
sex: "M",
},
minor:{
id: 4,
collegeRegion: "south",
}
});
更新特定的记录需要回调到之前的状态prevState
在这里:
setInfoData((prevState) => ({
...prevState,
major: {
...prevState.major,
name: "Tan Long",
}
}));
也许
setInfoData((prevState) => ({
...prevState,
major: {
...prevState.major,
name: "Tan Long",
},
minor: {
...prevState.minor,
collegeRegion: "northEast"
}));
我希望这对试图解决类似问题的人有所帮助。
您必须使用Rest参数和扩展语法(https://javascript.info/rest-parameters-spread)，并设置一个以preState作为setState参数的函数。
不起作用(功能缺失)
[state, setState] = useState({})
const key = 'foo';
const value = 'bar';
setState({
...state,
[key]: value
});
确实工作!
[state, setState] = useState({})
const key = 'foo';
const value = 'bar';
setState(prevState => ({
...prevState,
[key]: value
}));
我给您留下了一个实用函数来不可变地更新对象
/**
* Inmutable update object
* @param {Object} oldObject Object to update
* @param {Object} updatedValues Object with new values
* @return {Object} New Object with updated values
*/
export const updateObject = (oldObject, updatedValues) => {
return {
...oldObject,
...updatedValues
};
};
你可以这样用
const MyComponent = props => {
const [orderForm, setOrderForm] = useState({
specialities: {
elementType: "select",
elementConfig: {
options: [],
label: "Specialities"
},
touched: false
}
});
// I want to update the options list, to fill a select element
// ---------- Update with fetched elements ---------- //
const updateSpecialitiesData = data => {
// Inmutably update elementConfig object. i.e label field is not modified
const updatedOptions = updateObject(
orderForm[formElementKey]["elementConfig"],
{
options: data
}
);
// Inmutably update the relevant element.
const updatedFormElement = updateObject(orderForm[formElementKey], {
touched: true,
elementConfig: updatedOptions
});
// Inmutably update the relevant element in the state.
const orderFormUpdated = updateObject(orderForm, {
[formElementKey]: updatedFormElement
});
setOrderForm(orderFormUpdated);
};
useEffect(() => {
// some code to fetch data
updateSpecialitiesData.current("specialities",fetchedData);
}, [updateSpecialitiesData]);
// More component code
}
如果没有，您可以在这里找到更多实用程序:https://es.reactjs.org/docs/update.html
可以使用useReducer钩子来管理复杂的状态，而不是useState。要做到这一点，首先初始化状态和更新函数如下所示:
const initialState = { name: "Bob", occupation: "builder" };
const [state, updateState] = useReducer(
(state, updates) => ({ ...state, ...updates }),
initialState
);
然后你可以通过只传递部分更新来更新状态，就像这样:
updateState({ occupation: "postman" })
