如何使用PHP5类创建单例类?
当前回答
不幸的是,当有多个子类时,Inwdr的答案就失效了。
下面是一个正确的可继承单例基类。
class Singleton
{
private static $instances = array();
protected function __construct() {}
protected function __clone() {}
public function __wakeup()
{
throw new Exception("Cannot unserialize singleton");
}
public static function getInstance()
{
$cls = get_called_class(); // late-static-bound class name
if (!isset(self::$instances[$cls])) {
self::$instances[$cls] = new static;
}
return self::$instances[$cls];
}
}
测试代码:
class Foo extends Singleton {}
class Bar extends Singleton {}
echo get_class(Foo::getInstance()) . "\n";
echo get_class(Bar::getInstance()) . "\n";
其他回答
制作单例模式的真实和现代方法是:
<?php
/**
* Singleton Pattern.
*
* Modern implementation.
*/
class Singleton
{
/**
* Call this method to get singleton
*/
public static function instance()
{
static $instance = false;
if( $instance === false )
{
// Late static binding (PHP 5.3+)
$instance = new static();
}
return $instance;
}
/**
* Make constructor private, so nobody can call "new Class".
*/
private function __construct() {}
/**
* Make clone magic method private, so nobody can clone instance.
*/
private function __clone() {}
/**
* Make sleep magic method private, so nobody can serialize instance.
*/
private function __sleep() {}
/**
* Make wakeup magic method private, so nobody can unserialize instance.
*/
private function __wakeup() {}
}
现在你可以用它。
<?php
/**
* Database.
*
* Inherited from Singleton, so it's now got singleton behavior.
*/
class Database extends Singleton {
protected $label;
/**
* Example of that singleton is working correctly.
*/
public function setLabel($label)
{
$this->label = $label;
}
public function getLabel()
{
return $this->label;
}
}
// create first instance
$database = Database::instance();
$database->setLabel('Abraham');
echo $database->getLabel() . PHP_EOL;
// now try to create other instance as well
$other_db = Database::instance();
echo $other_db->getLabel() . PHP_EOL; // Abraham
$other_db->setLabel('Priler');
echo $database->getLabel() . PHP_EOL; // Priler
echo $other_db->getLabel() . PHP_EOL; // Priler
正如你所看到的,这种实现更加灵活。
我喜欢使用trait的@jose-segura方法,但不喜欢在子类上定义静态变量的需要。下面是一个解决方案,通过将实例缓存在一个静态局部变量中到按类名索引的工厂方法中来避免这种情况:
<?php
trait Singleton {
# Single point of entry for creating a new instance. For a given
# class always returns the same instance.
public static function instance(){
static $instances = array();
$class = get_called_class();
if( !isset($instances[$class]) ) $instances[$class] = new $class();
return $instances[$class];
}
# Kill traditional methods of creating new instances
protected function __clone() {}
protected function __construct() {}
}
用法与@jose-segura相同,只是在子类中不需要静态变量。
/**
* Singleton class
*
*/
final class UserFactory
{
private static $inst = null;
// Prevent cloning and de-serializing
private function __clone(){}
private function __wakeup(){}
/**
* Call this method to get singleton
*
* @return UserFactory
*/
public static function Instance()
{
if ($inst === null) {
$inst = new UserFactory();
}
return $inst;
}
/**
* Private ctor so nobody else can instantiate it
*
*/
private function __construct()
{
}
}
使用方法:
$fact = UserFactory::Instance();
$fact2 = UserFactory::Instance();
$fact == $fact2;
But:
$fact = new UserFactory()
抛出错误。
参见http://php.net/manual/en/language.variables.scope.php#language.variables.scope.static了解静态变量的作用域以及为什么设置static $inst = null;的工作原理。
你可能应该添加一个私有的__clone()方法来禁止克隆实例。
private function __clone() {}
如果您不包含此方法,则可能出现以下情况
$inst1=UserFactory::Instance(); // to stick with the example provided above
$inst2=clone $inst1;
现在$inst1 !== $inst2 -它们不再是同一个实例了。
PHP 5.3允许通过后期静态绑定创建可继承的单例类:
class Singleton
{
protected static $instance = null;
protected function __construct()
{
//Thou shalt not construct that which is unconstructable!
}
protected function __clone()
{
//Me not like clones! Me smash clones!
}
public static function getInstance()
{
if (!isset(static::$instance)) {
static::$instance = new static;
}
return static::$instance;
}
}
这解决了一个问题,在PHP 5.3之前,任何扩展了Singleton的类都会生成父类的实例,而不是它自己的实例。
现在你可以做:
class Foobar extends Singleton {};
$foo = Foobar::getInstance();
$foo将是Foobar的一个实例而不是Singleton的一个实例。