你可能应该添加一个私有的__clone()方法来禁止克隆实例。

private function __clone() {}

如果您不包含此方法，则可能出现以下情况

$inst1=UserFactory::Instance(); // to stick with the example provided above
$inst2=clone $inst1;

现在$inst1 !== $inst2 -它们不再是同一个实例了。

下面是我的例子，它提供了调用as $var = new Singleton()的能力，并创建了3个变量来测试它是否创建了新对象:

class Singleton{

    private static $data;

    function __construct(){
        if ($this::$data == null){
            $this->makeSingleton();
        }
        echo "<br/>".$this::$data;
    }

    private function makeSingleton(){
        $this::$data = rand(0, 100);
    }

    public function change($new_val){
        $this::$data = $new_val;
    }

    public function printme(){
        echo "<br/>".$this::$data;
    }

}


$a = new Singleton();
$b = new Singleton();
$c = new Singleton();

$a->change(-2);
$a->printme();
$b->printme();

$d = new Singleton();
$d->printme();

PHP 5.3允许通过后期静态绑定创建可继承的单例类:

class Singleton
{
    protected static $instance = null;

    protected function __construct()
    {
        //Thou shalt not construct that which is unconstructable!
    }

    protected function __clone()
    {
        //Me not like clones! Me smash clones!
    }

    public static function getInstance()
    {
        if (!isset(static::$instance)) {
            static::$instance = new static;
        }
        return static::$instance;
    }
}

这解决了一个问题，在PHP 5.3之前，任何扩展了Singleton的类都会生成父类的实例，而不是它自己的实例。

现在你可以做:

class Foobar extends Singleton {};
$foo = Foobar::getInstance();

$foo将是Foobar的一个实例而不是Singleton的一个实例。

这是在数据库类上创建单例的例子

设计模式 1)单

class Database{
  public static $instance;
  public static function getInstance(){
    if(!isset(Database::$instance)){
    Database::$instance=new Database();

     return Database::$instance;
    }

  }

  $db=Database::getInstance();
  $db2=Database::getInstance();
  $db3=Database::getInstance();

  var_dump($db);
  var_dump($db2);
  var_dump($db3);

那么输出是

  object(Database)[1]
  object(Database)[1]
  object(Database)[1]

只使用单个实例，不要创建3个实例

class Database{

        //variable to hold db connection
        private $db;
        //note we used static variable,beacuse an instance cannot be used to refer this
        public static $instance;

        //note constructor is private so that classcannot be instantiated
        private function __construct(){
          //code connect to database  

         }     

         //to prevent loop hole in PHP so that the class cannot be cloned
        private function __clone() {}

        //used static function so that, this can be called from other classes
        public static function getInstance(){

            if( !(self::$instance instanceof self) ){
                self::$instance = new self();           
            }
             return self::$instance;
        }


        public function query($sql){
            //code to run the query
        }

    }


Access the method getInstance using
$db = Singleton::getInstance();
$db->query();

不幸的是，当有多个子类时，Inwdr的答案就失效了。

下面是一个正确的可继承单例基类。

class Singleton
{
    private static $instances = array();
    protected function __construct() {}
    protected function __clone() {}
    public function __wakeup()
    {
        throw new Exception("Cannot unserialize singleton");
    }

    public static function getInstance()
    {
        $cls = get_called_class(); // late-static-bound class name
        if (!isset(self::$instances[$cls])) {
            self::$instances[$cls] = new static;
        }
        return self::$instances[$cls];
    }
}

测试代码:

class Foo extends Singleton {}
class Bar extends Singleton {}

echo get_class(Foo::getInstance()) . "\n";
echo get_class(Bar::getInstance()) . "\n";