如何使用PHP5类创建单例类?
当前回答
下面是我的例子,它提供了调用as $var = new Singleton()的能力,并创建了3个变量来测试它是否创建了新对象:
class Singleton{
private static $data;
function __construct(){
if ($this::$data == null){
$this->makeSingleton();
}
echo "<br/>".$this::$data;
}
private function makeSingleton(){
$this::$data = rand(0, 100);
}
public function change($new_val){
$this::$data = $new_val;
}
public function printme(){
echo "<br/>".$this::$data;
}
}
$a = new Singleton();
$b = new Singleton();
$c = new Singleton();
$a->change(-2);
$a->printme();
$b->printme();
$d = new Singleton();
$d->printme();
其他回答
下面是我的例子,它提供了调用as $var = new Singleton()的能力,并创建了3个变量来测试它是否创建了新对象:
class Singleton{
private static $data;
function __construct(){
if ($this::$data == null){
$this->makeSingleton();
}
echo "<br/>".$this::$data;
}
private function makeSingleton(){
$this::$data = rand(0, 100);
}
public function change($new_val){
$this::$data = $new_val;
}
public function printme(){
echo "<br/>".$this::$data;
}
}
$a = new Singleton();
$b = new Singleton();
$c = new Singleton();
$a->change(-2);
$a->printme();
$b->printme();
$d = new Singleton();
$d->printme();
PHP 5.3允许通过后期静态绑定创建可继承的单例类:
class Singleton
{
protected static $instance = null;
protected function __construct()
{
//Thou shalt not construct that which is unconstructable!
}
protected function __clone()
{
//Me not like clones! Me smash clones!
}
public static function getInstance()
{
if (!isset(static::$instance)) {
static::$instance = new static;
}
return static::$instance;
}
}
这解决了一个问题,在PHP 5.3之前,任何扩展了Singleton的类都会生成父类的实例,而不是它自己的实例。
现在你可以做:
class Foobar extends Singleton {};
$foo = Foobar::getInstance();
$foo将是Foobar的一个实例而不是Singleton的一个实例。
/**
* Singleton class
*
*/
final class UserFactory
{
private static $inst = null;
// Prevent cloning and de-serializing
private function __clone(){}
private function __wakeup(){}
/**
* Call this method to get singleton
*
* @return UserFactory
*/
public static function Instance()
{
if ($inst === null) {
$inst = new UserFactory();
}
return $inst;
}
/**
* Private ctor so nobody else can instantiate it
*
*/
private function __construct()
{
}
}
使用方法:
$fact = UserFactory::Instance();
$fact2 = UserFactory::Instance();
$fact == $fact2;
But:
$fact = new UserFactory()
抛出错误。
参见http://php.net/manual/en/language.variables.scope.php#language.variables.scope.static了解静态变量的作用域以及为什么设置static $inst = null;的工作原理。
我很久以前就写过,想在这里分享
class SingletonDesignPattern {
//just for demo there will be only one instance
private static $instanceCount =0;
//create the private instance variable
private static $myInstance=null;
//make constructor private so no one create object using new Keyword
private function __construct(){}
//no one clone the object
private function __clone(){}
//avoid serialazation
public function __wakeup(){}
//ony one way to create object
public static function getInstance(){
if(self::$myInstance==null){
self::$myInstance=new SingletonDesignPattern();
self::$instanceCount++;
}
return self::$myInstance;
}
public static function getInstanceCount(){
return self::$instanceCount;
}
}
//now lets play with singleton design pattern
$instance = SingletonDesignPattern::getInstance();
$instance = SingletonDesignPattern::getInstance();
$instance = SingletonDesignPattern::getInstance();
$instance = SingletonDesignPattern::getInstance();
echo "number of instances: ".SingletonDesignPattern::getInstanceCount();
我同意第一个答案,但我也会将类声明为final,这样它就不能被扩展,因为扩展单例违背了单例模式。此外,实例变量应该是私有的,这样就不能直接访问它。还要将__clone方法设为私有,这样就不能克隆单例对象。
下面是一些示例代码。
/**
* Singleton class
*
*/
final class UserFactory
{
private static $_instance = null;
/**
* Private constructor
*
*/
private function __construct() {}
/**
* Private clone method
*
*/
private function __clone() {}
/**
* Call this method to get singleton
*
* @return UserFactory
*/
public static function getInstance()
{
if (self::$_instance === null) {
self::$_instance = new UserFactory();
}
return self::$_instance;
}
}
示例使用
$user_factory = UserFactory::getInstance();
这阻止你做什么(这将违反单例模式..
你不能这么做!
$user_factory = UserFactory::$_instance;
class SecondUserFactory extends UserFactory { }