我有一个包含枚举属性的类，在使用JavaScriptSerializer序列化对象时，我的json结果包含枚举的整数值，而不是它的字符串“name”。有没有一种方法来获得枚举作为字符串在我的json而不必创建一个自定义JavaScriptConverter?也许有一个属性，我可以装饰枚举定义，或对象属性?
举个例子:
enum Gender { Male, Female }
class Person
{
int Age { get; set; }
Gender Gender { get; set; }
}
期望的JSON结果:
{ "Age": 35, "Gender": "Male" }
理想情况下，用内置的。net框架类来寻找答案，如果没有可能的替代方案(如Json.net)也是受欢迎的。
当前回答
对于任何在22年5月就需要。net 6解决方案并且仍在使用Newtonsoft的人来说，你可以像这样全局注册转换器:
var builder = WebApplication.CreateBuilder(args);
...
builder.Services.AddControllers(options => options.RespectBrowserAcceptHeader = true)
.AddNewtonsoftJson(opt =>
{
opt.SerializerSettings.ContractResolver = new DefaultContractResolver();
opt.SerializerSettings.Converters.Add(new Newtonsoft.Json.Converters.StringEnumConverter());
})
.AddXmlSerializerFormatters()
.AddXmlDataContractSerializerFormatters();
其他回答
下面是newtonsoft.json的答案
enum Gender { Male, Female }
class Person
{
int Age { get; set; }
[JsonConverter(typeof(StringEnumConverter))]
Gender Gender { get; set; }
}
new JavaScriptSerializer().Serialize(
(from p
in (new List<Person>() {
new Person()
{
Age = 35,
Gender = Gender.Male
}
})
select new { Age =p.Age, Gender=p.Gender.ToString() }
).ToArray()[0]
);
这个版本的Stephen的回答没有改变JSON中的名称:
[DataContract(
Namespace =
"http://schemas.datacontract.org/2004/07/Whatever")]
class Person
{
[DataMember]
int Age { get; set; }
Gender Gender { get; set; }
[DataMember(Name = "Gender")]
string GenderString
{
get { return this.Gender.ToString(); }
set
{
Gender g;
this.Gender = Enum.TryParse(value, true, out g) ? g : Gender.Male;
}
}
}
将以下内容添加到全局中。asax用于JSON序列化c# enum为字符串
HttpConfiguration config = GlobalConfiguration.Configuration;
config.Formatters.JsonFormatter.SerializerSettings.Formatting =
Newtonsoft.Json.Formatting.Indented;
config.Formatters.JsonFormatter.SerializerSettings.Converters.Add
(new Newtonsoft.Json.Converters.StringEnumConverter());
Person p = new Person();
p.Age = 35;
p.Gender = Gender.Male;
//1. male="Male";
string male = Gender.Male.ToString();
p.Gender = Gender.Female;
//2. female="Female";
string female = Enum.GetName(typeof(Gender), p.Gender);
JObject jobj = new JObject();
jobj["Age"] = p.Age;
jobj["Gender"] = male;
jobj["Gender2"] = female;
//you result: josn= {"Age": 35,"Gender": "Male","Gender2": "Female"}
string json = jobj.ToString();
