我有一个包含10个元素的数组X。我想创建一个新数组，包含X中从索引3开始并在索引7结束的所有元素。当然，我可以很容易地写一个循环，将它为我，但我想保持我的代码尽可能干净。c#中有一个方法可以帮我做这个吗?
类似(伪代码):
Array NewArray = oldArray.createNewArrayFromRange(int BeginIndex , int EndIndex)
数组中。拷贝不符合我的需要。我需要在新数组中的项目是克隆。数组中。copy只是一个c风格的memcpy等效，这不是我要找的。
当前回答
你可以参加微软的课程:
internal class Set<TElement>
{
private int[] _buckets;
private Slot[] _slots;
private int _count;
private int _freeList;
private readonly IEqualityComparer<TElement> _comparer;
public Set()
: this(null)
{
}
public Set(IEqualityComparer<TElement> comparer)
{
if (comparer == null)
comparer = EqualityComparer<TElement>.Default;
_comparer = comparer;
_buckets = new int[7];
_slots = new Slot[7];
_freeList = -1;
}
public bool Add(TElement value)
{
return !Find(value, true);
}
public bool Contains(TElement value)
{
return Find(value, false);
}
public bool Remove(TElement value)
{
var hashCode = InternalGetHashCode(value);
var index1 = hashCode % _buckets.Length;
var index2 = -1;
for (var index3 = _buckets[index1] - 1; index3 >= 0; index3 = _slots[index3].Next)
{
if (_slots[index3].HashCode == hashCode && _comparer.Equals(_slots[index3].Value, value))
{
if (index2 < 0)
_buckets[index1] = _slots[index3].Next + 1;
else
_slots[index2].Next = _slots[index3].Next;
_slots[index3].HashCode = -1;
_slots[index3].Value = default(TElement);
_slots[index3].Next = _freeList;
_freeList = index3;
return true;
}
index2 = index3;
}
return false;
}
private bool Find(TElement value, bool add)
{
var hashCode = InternalGetHashCode(value);
for (var index = _buckets[hashCode % _buckets.Length] - 1; index >= 0; index = _slots[index].Next)
{
if (_slots[index].HashCode == hashCode && _comparer.Equals(_slots[index].Value, value))
return true;
}
if (add)
{
int index1;
if (_freeList >= 0)
{
index1 = _freeList;
_freeList = _slots[index1].Next;
}
else
{
if (_count == _slots.Length)
Resize();
index1 = _count;
++_count;
}
int index2 = hashCode % _buckets.Length;
_slots[index1].HashCode = hashCode;
_slots[index1].Value = value;
_slots[index1].Next = _buckets[index2] - 1;
_buckets[index2] = index1 + 1;
}
return false;
}
private void Resize()
{
var length = checked(_count * 2 + 1);
var numArray = new int[length];
var slotArray = new Slot[length];
Array.Copy(_slots, 0, slotArray, 0, _count);
for (var index1 = 0; index1 < _count; ++index1)
{
int index2 = slotArray[index1].HashCode % length;
slotArray[index1].Next = numArray[index2] - 1;
numArray[index2] = index1 + 1;
}
_buckets = numArray;
_slots = slotArray;
}
internal int InternalGetHashCode(TElement value)
{
if (value != null)
return _comparer.GetHashCode(value) & int.MaxValue;
return 0;
}
internal struct Slot
{
internal int HashCode;
internal TElement Value;
internal int Next;
}
}
然后
public static T[] GetSub<T>(this T[] first, T[] second)
{
var items = IntersectIteratorWithIndex(first, second);
if (!items.Any()) return new T[] { };
var index = items.First().Item2;
var length = first.Count() - index;
var subArray = new T[length];
Array.Copy(first, index, subArray, 0, length);
return subArray;
}
private static IEnumerable<Tuple<T, Int32>> IntersectIteratorWithIndex<T>(IEnumerable<T> first, IEnumerable<T> second)
{
var firstList = first.ToList();
var set = new Set<T>();
foreach (var i in second)
set.Add(i);
foreach (var i in firstList)
{
if (set.Remove(i))
yield return new Tuple<T, Int32>(i, firstList.IndexOf(i));
}
}
其他回答
在c# 8中，他们引入了一个新的范围和索引类型，可以这样使用:
int[] a = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
Index i1 = 3; // number 3 from beginning
Index i2 = ^4; // number 4 from end
var slice = a[i1..i2]; // { 3, 4, 5 }
引用:
https://learn.microsoft.com/en-us/dotnet/core/whats-new/dotnet-core-3-0#ranges-and-indices https://devblogs.microsoft.com/dotnet/building-c-8-0/
以Marc的回答为基础，但加入了想要的克隆行为
public static T[] CloneSubArray<T>(this T[] data, int index, int length)
where T : ICloneable
{
T[] result = new T[length];
for (int i = 0; i < length; i++)
{
var original = data[index + i];
if (original != null)
result[i] = (T)original.Clone();
return result;
}
如果实现ICloneable太辛苦了，那么可以使用Håvard Stranden的Copyable库来完成所需的繁重工作。
using OX.Copyable;
public static T[] DeepCopySubArray<T>(
this T[] data, int index, int length)
{
T[] result = new T[length];
for (int i = 0; i < length; i++)
{
var original = data[index + i];
if (original != null)
result[i] = (T)original.Copy();
return result;
}
注意，OX.Copyable实现适用于以下任何一种:
然而，为了让自动复制工作，以下语句之一必须成立，例如: 它的类型必须有一个无参数构造函数，或者 它必须是可复制的，或者 它必须为其类型注册一个IInstanceProvider。
所以这应该适用于你遇到的任何情况。如果你克隆的对象子图中包含db连接或文件/流句柄，你显然有问题，但这对任何广义深度复制都是真的。
如果你想使用其他深度复制方法，本文列出了其他几种方法，所以我建议你不要尝试自己编写。
string[] arr = { "Parrot" , "Snake" ,"Rabbit" , "Dog" , "cat" };
arr = arr.ToList().GetRange(0, arr.Length -1).ToArray();
这是我发现的最佳方法:
private void GetSubArrayThroughArraySegment() {
int[] array = { 10, 20, 30 };
ArraySegment<int> segment = new ArraySegment<int>(array, 1, 2);
Console.WriteLine("-- Array --");
int[] original = segment.Array;
foreach (int value in original)
{
Console.WriteLine(value);
}
Console.WriteLine("-- Offset --");
Console.WriteLine(segment.Offset);
Console.WriteLine("-- Count --");
Console.WriteLine(segment.Count);
Console.WriteLine("-- Range --");
for (int i = segment.Offset; i <= segment.Count; i++)
{
Console.WriteLine(segment.Array[i]);
}
}
希望有帮助!
